Answer:
THANK YOU SO MUCH! I AM ON MY CHROME BOOK RIGHT NOW AND WAS HESITATING TO DOWNLOAD THE UPDATE!
Explanation:
The answer is Benching.
Benching and sloping are methods used to protect employees working in excavations from cave–ins. Benches are cuts in the slope that provides protection by removing material at an angle to its floor. They give the slope a stair-step appearance with emphasis on the angles; the flatter the angle, the more the protection. Benches are split into two groups: simple and multiple.
Electronic component on a computer's
motherboard that interprets and carries
out the basic instructions that operate
the computer; also called processor.
A component which is most likely to allow both physical and virtual machines to communicate with each other is a: virtual switch.
<h3>What is virtualization?</h3>
Virtualization can be defined as the creation of an abstract layer over computer hardware primarily through the use of a software, in order to enable the operating system (OS), storage device, server, etc., to be used by end users over the Internet.
In Cloud computing, some of the components (features) which is not required for a successful virtualization environment include the following:
In conclusion, we can infer and logically deduce that a component which is most likely to allow both physical and virtual machines to communicate with each other is a virtual switch because it enables the virtual servers and the desktops to communicate.
Read more on virtualization here: brainly.com/question/14229248
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Complete Question:
Which component is most likely to allow physical and virtual machines to communicate with each other?
VHD.
Virtual switch.
Hyper V.
Host OS.
Answer:
see explaination
Explanation:
I made use of python program to solve this.
text file name with fun.txt.
6 fun. 3 hello 10 <> 2 25 4 wow!
Program code:
import re
file = open('fun.txt','r') #for reading file
strings="" #declaring empty string
for k in file:
strings=strings+k #all character in file is storing in strings variable for do operations
pattern = '\s' #for pattern \s is for space
result = re.split(pattern, strings) #split the string with space
for k in range(len(result)): #loop through the list of string
if(k%2) == 0: #checking for integer to time of string
p=int(result[k])
print(result[k+1] *p) #print times of the string(k+1)
Check attachment for output
