Vertex:(-1,-4)
Concavity: up
Domain: -♾< x < ♾
Range: y > (or equal to) -4
Roots: (-3,0) (1,0)
Factors: (x + 3) (x - 1)
Equation: x^2 + 2x - 3
Answer:
Step-by-step explanation:
11 - 19 - 4 - (-8) =
11 - 19 - 4 + 8 =
- 23 + 19 =
- 4 <===
Answer:
gcf is ![3m^2n](https://tex.z-dn.net/?f=3m%5E2n)
Step-by-step explanation:
we are given
and ![81m^2n^2](https://tex.z-dn.net/?f=81m%5E2n%5E2)
Firstly, we will find factors of both expression
![48m^5n=2\times 2\times2\times 2\times 3\times m^2\times m^3\times n](https://tex.z-dn.net/?f=48m%5E5n%3D2%5Ctimes%202%5Ctimes2%5Ctimes%202%5Ctimes%203%5Ctimes%20m%5E2%5Ctimes%20m%5E3%5Ctimes%20n)
![81m^2n^2=3\times 3\times 3\times 3\times m^2\times n\times n](https://tex.z-dn.net/?f=81m%5E2n%5E2%3D3%5Ctimes%203%5Ctimes%203%5Ctimes%203%5Ctimes%20m%5E2%5Ctimes%20n%5Ctimes%20n)
now, we will find common factors among them
we can see that
For finding gcf, we always find common factors
so,
common terms are 3,m^2 and n
so, gcf is
![=3\times m^2\times n](https://tex.z-dn.net/?f=%3D3%5Ctimes%20m%5E2%5Ctimes%20n)
![=3m^2n](https://tex.z-dn.net/?f=%3D3m%5E2n)
Answer:
(i) 28. (ii) 34. (iii) 42.5
Step-by-step explanation:
![first \: quartiles \: = \frac{1}{4} \times sum \: of \: the \: data](https://tex.z-dn.net/?f=first%20%5C%3A%20quartiles%20%5C%3A%20%20%3D%20%20%5Cfrac%7B1%7D%7B4%7D%20%20%5Ctimes%20sum%20%5C%3A%20of%20%5C%3A%20the%20%5C%3A%20data)
11/12 and 1/8
we only need to look at the denominators which is
12 and 8
12 24 36
8 16 <span> 24
</span>so the LCD is 24