The term in that equation is 3x 7x and -9 hope this helps
Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8
Answer:
ummm i don't see anything
N = -3
5n + n + 6 = -18 - 2n
6n + 6 = -18 - 2n
-6 to both sides
6n = -24 - 2n
+2n to both sides
8n = -24
divide 8 to both sides
n = -3
Answer:
8:30
Step-by-step explanation:
well it's a delay so you will have to add
6:30 + 2 = 8:30
