Question

write the slope-intercept form of the line that passes through the point (1,0) and is parallel to x-y=7. type your answer in the box provided or use the upload option to submit your solution

Answer 1

We know that a parallel line has the same slope. And the slope-intercept form in y=mx+b.

1. simplify x-y=7 to isolate y.

subtract x:    -y=-x+7

then divide by -1:  y=x-7

so the slope is 1 (m=1)

2. plug in m=1 and (1,0)           *******alternate solution below

0=1(1)+b

0=1+b    subtract 1

-1=b    (b=-1)

3.  y=mx+b plug in numbers. ( in bold)

y=1x-1

your answer is y=x-1

*****alternate answer solution from step 2 (using step 1)

2. use the formula y-y1=m(x-x1) (y1 and x1 is with the 1 below the letters BTW)

plug in (1,0)

y-0=1(x-1)

y=1x-1

y=x-1 is your answer.

So it comes out as the same answer. Just 2 different ways to doing it! :)

Answer 2

• Parallel lines have the same slope but different y intercepts.
• turn x-y=7 into slope intercept form by isolating y which would be -y=-x+7
• divide the equation by -1 in order to make y positive and you get y=x-7
• So rewrite the equation with the same slope but this time solving for b
• y=x+b
• plug in your coordinates
• 0=1+b
• subtract 1 from both sides
• -1=b
• so your equation would be
• y=x-1