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goldfiish [28.3K]
3 years ago
8

assume that a password to log onto a computer account is to consist of any 4 digits or letters (repetition is permitted). Determ

ine the number of passwords possible if the letters
Mathematics
1 answer:
boyakko [2]3 years ago
3 0

Answer:

24

Step-by-step explanation:

if you were to use your calculator and applied n! after the number it should give u the answer

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NEED HELP ASAP PLS!
Ad libitum [116K]

Answer:

All of them

Step-by-step explanation:

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3 years ago
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Rewrite 18/14 in simplest form
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You would divide them both my two to get 9/7
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Consider a binomial experiment with n = 20 and p = .70.
jolli1 [7]

Complete question:

Consider a binomial experiment with n = 20 and p = .70.

A. Compute f(12).

B. Compute f(16).

C. Compute P(x≥ 16).

D. Compute P(x≤15).

E. Compute E(x).

F. Compute Var(x).

Answer:

a) 0.1144

b) 0.1304

c) 0.2375

d) 0.7625

e) 14

f) 4.2

Step-by-step explanation:

Given:

n = 20

p = 0.70

q = 1 - p ==>  1 - 0.70 = 0.30

a) Use the formula:

P(x) = CC\left(\begin{array}{ccc}n\\x\end{array}\right) p^x q^(^n^-^x^)

Thus,

P(12) = C\left(\begin{array}{ccc}20\\12\end{array}\right) (0.7^1^2) (0.3^(^2^0^-^1^2^) )

= 125970*0.0138*0.00006

= 0.1144

b) P(16) = C\left(\begin{array}{ccc}20\\16\end{array}\right) 0.7^1^6 (0.3^(^2^0^-^1^6^))

= 4845 * 0.0033 * 0.0081

= 0.1304

c) Compute P(x≥16):

P(x ≥ 16) = P(16) + P(17) + P(18) + P(19) + P(20)

= C\left(\begin{array}{ccc}20\\16\end{array}\right) 0.7^1^6 (0.3^(^2^0^-^1^6^)) + C\left(\begin{array}{ccc}20\\17\end{array}\right) 0.7^1^7 (0.3^(^2^0^-^1^7^) ) + C\left(\begin{array}{ccc}20\\18\end{array}\right) 0.7^1^8 (0.3^(^2^0^-^1^8^)) + C\left(\begin{array}{ccc}20\\19\end{array}\right) 0.7^1^9 (0.3^(^2^0^-^1^9^)) + C\left(\begin{array}{ccc}20\\20\end{array}\right) 0.7^2^0 (0.3^(^2^0^-^2^0^))

= 0.1304 + 0.0716 + 0.0278 + 0.0068 + 0.0008 = 0.2375

d) P(x ≤ 15):

= 1 - P(x ≥ 16)

= 1 - 0.2375

= 0.7625

e) E(x): use the formula, n * p.

= n*p

= 20 * 0.7

= 14

f) Var(x)

Use the formula: npq

npq = 20 * 0.7 * 0.3

= 4.2

σ

5 0
4 years ago
A total of 376 tickets were sold for the school play. they were either adult tickets or student tickets. the number of student t
inysia [295]
3x + x = 376 
4x=376
x=94
Number of student tickets sold = 94 * 3 = 282
Number of adult tickets sold= 94
3 0
3 years ago
NEED ASAP PLEASE
olga nikolaevna [1]

Answer:

15

15x4 + 10 =

8 0
3 years ago
Read 2 more answers
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