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Andrew [12]
3 years ago
15

What are some examples of how you have used, or could use, algebraic equations to solve problems in your everyday life?

Mathematics
1 answer:
pshichka [43]3 years ago
3 0
We use algebraic equations in our daily lives without knowing it. For example, when we go shopping, calculate grocery expenses, or even fill our gas tanks, we are using equations. Let's say we needed to fill our gas tank, but we only had $15.00 to do so. If the price of gas is $3.00 per gallon, how many gallons could we buy? We use the simply algebraic equation of \frac{x}{y} to calculate the total gallons that can be bought. x = the money we have. y = price per gallon of gas. \frac{15}{3} = 5. So with $15.00, we can buy 5 gallons of gas; and that is just one example of using an algebraic equation in everyday life!
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A local hamburger shop sold a combined total of 763 hamburgers and cheeseburgers on Saturday. There were 63 more cheeseburgers s
Airida [17]
In order to solve this we'll start by assigning variables to hamburgers and cheeseburgers, since these are what we're trying to find. Lets say x = hamburgers and y = cheeseburgers. So we know two things, we know that x+y= 763 (hamburgers plus cheeseburgers sold equals 763, and we know that y= x+63 (cheeseburgers sold equals 63 more than hamburgers sold). Now we have a system of equations. This can be solved most easily by rearranging each equation to each y, and then set them equal to each other:
x+y=763 -> y=763-x, and we already have y=x+63. Set them equal to each other:
x+63 = 763-x (add x to both sides) -> 2x+63 = 763 (subtract 63 from both sides) -> 2x = 700 (divide both sides by 2) x = 350. So we solved for x, which is hamburgers sold, which is what the question asks for, so your answer is 350 hamburgers were sold on Saturday
6 0
3 years ago
Alemu, Tulu, Kassa and Tegitu worked for 4 hours, 6 hours, 5 hours
GaryK [48]
As a group they were paid $1000 after putting in 4+6+5+5 = 20 worker-hours.
$1000/(20 worker-hours) = $50/(worker-hour)
Alemu received 4*$50 = $200
Tulu received 6*$50 = $300
Kassa and Tegitu each received 5*$50 = $250
6 0
3 years ago
General house cleaning (sweeping the floors, vacuuming, laundry etc.)
kobusy [5.1K]

Answer:

sleeping the floor and vacuuming

7 0
3 years ago
A 4 pack of toy cars cost 3.64. What is the unit price
marissa [1.9K]

Answer:0.91

Step-by-step explanation:

3.64/4=0.91

unit price=cost of one item/thing

5 0
1 year ago
Find the number of elements in A1 ∪A2 ∪A3 if there are 100 elements in A1, 1000 in A2, and 10,000 in A3 if a) A1 ⊆ A2 and A2 ⊆ A
Stella [2.4K]

Answer:

Step-by-step explanation:

Given that there are 3 sets such that  there are 100 elements in A1, 1000 in A2, and 10,000 in A3

a) If A1 ⊆ A2 and A2 ⊆ A3

then union will contain the same number of elements as that of A3

i.e. n(A1 ∪A2 ∪A3)=n(A3) =10000

b) If the sets are pairwise disjoint.

union will contain the sum of elements of each set

n(A1 ∪A2 ∪A3) = 100+1000+10000=11100

c) If there are two elements common to each pair of sets and one element in all three sets

We subtract common elements pairwise and add common element in 3

i.e. n(A1 ∪A2 ∪A3) = 100+1000+10000-2-2-2+1\\= 10995

5 0
3 years ago
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