How did the code of Hammurabi benefit Hammurabi?

Blake and James are planning to go on a trip. Blake already has some money saved. She earns $96 more by working overtime. James

rosijanka [135]

Blake saved $\bold{\$ 433.80}$

Option - A

SOLUTION:

Given, Blake and James are planning to go on a trip.

Blake already has some money saved.

Let the amount saved by Blake be $\$ n$ .

She earns $\$96$ more by working overtime.

Then, total amount by Blake $=\$(n+96)$

James has $\$ 53$ more than 4 times the amount of money that Blake has saved.

Then, total amount by James will be $\$ 53+4 \times \$ n=\$(4 n+53)$

If they have $\$2,318$ in all, we have to find how much money had Blake originally saved

Now, total amount = $\$2318$

$\begin{array}{l}{\rightarrow \text { Amount by Blake }+\text { amount by James }=2318} \\\\ {\rightarrow \mathrm{n}+96+4 \mathrm{n}+53=2318 \rightarrow 5 \mathrm{n}+149=2318 \rightarrow 5 \mathrm{n}=2318-149 \rightarrow 5 \mathrm{n}=2169 \rightarrow \mathrm{n}=433.8}\end{array}$

7 0

4 years ago

EASY PLS HELP WILL GIVE BRAINLY If -11 + N = -11, then N is the _____.

Tems11 [23]

Answer:

SteIf -11 + N = -11 then N is the additive inverse because if we do process of elimination (POE) we can cross out C and D because this is a addition problem not a multiplication, and we know its not B because that's like 99 + 0 = 99 set, but instead its A because its just like -8 + 8 = 0. (If this was not a multiple choice question then tell me)

3 0

3 years ago

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Find the GCF of the terms of the polynomial. 30x3 + 16x5 a. x3 b. 2x3 c. 2x5 d. 16x

Vladimir79 [104]

You can take out 2x^3 from both terms making it
2x^3 (15+8x^2)
Answer is B

3 0

3 years ago

g A 5 foot tall man walks at 10 ft/s toward a street light that is 20 ft above the ground. What is the rate of change of the len

vredina [299]

Answer:

$-\frac{10}{3}ft/s$

Step-by-step explanation:

We are given that

Height of man=5 foot

$\frac{dy}{dt}=-10ft/s$

Height of street light=20ft

We have to find the rate of change of the length of his shadow when he is 25 ft form the street light.

ABE and CDE are similar triangle because all right triangles are similar.

$\frac{20}{5}=\frac{x+y}{x}$

$4=\frac{x+y}{x}$

$4x=x+y$

$4x-x=y$

$3x=y$

$3\frac{dx}{dt}=\frac{dy}{dt}$

$\frac{dx}{dt}=\frac{1}{3}(-10)=-\frac{10}{3}ft/s=-\frac{10}{3}ft/s$

Hence, the rate of change of the length of his shadow when he is 25 ft from the street light= $-\frac{10}{3}ft/s$

7 0

3 years ago

Is the expression 2f + 4f + 2 – 3 equivalent to 6f – 1? 6f – 1 evaluated at f = 9 is 53. 2f + 4f + 2 – 3 evaluated at f = 9 is a

morpeh [17]

We have that

the expression 2f + 4f + 2 – 3-------> we can group it (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]

if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17

let's check it
[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok

6 0

4 years ago

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