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Setler79 [48]
4 years ago
13

An object is transported to three different planets in our solar system. Which of the following is true about that object?

Physics
1 answer:
Alisiya [41]4 years ago
3 0

-- The object's weight is different on each planet, while it is
apparently weightless during the trips in between.

-- On some if not all of the three planets, the object needs to be
surrounded by protection from heat, cold, poisonous gases, or
solar radiation.

-- If the object is any kind of life form, then its circadian rhythm is
all screwed up, and it is having trouble sleeping.

-- The object has accumulated a huge balance of frequent flier miles.

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What you filling your heart with <br>oxygen and blood
svlad2 [7]

Answer:

Explanation:

                    The right side of your heart receives oxygen-poor blood from your veins and pumps it to your lungs, where it picks up oxygen and gets rid of carbon dioxide. The left side of your heart receives oxygen-rich blood from your lungs and pumps it through your arteries to the rest of your body.

        #I AM ILLITERATE

5 0
3 years ago
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A planet of mass m moves around the Sun of mass M in an elliptical orbit. The maximum and minimum distance of the planet from th
zzz [600]

Answer:

the relation between the time period of the planet is

T = 2π √[( r1 + r2 )³ / 8GM ]

Explanation:

Given the data i  the question;

mass of sun = M

minimum and maximum distance = r1 and r2 respectively

Now, using Kepler's third law,

" the square of period T of any planet is proportional to the cube of average distance "

T² ∝ R³

average distance a = ( r1 + r2 ) / 2

we know that

T² = 4π²a³ / GM

T² = 4π² [( ( r1 + r2 ) / 2 )³ / GM ]

T² = 4π² [( ( r1 + r2 )³ / 8 ) / GM ]

T² = 4π² [( r1 + r2 )³ / 8GM ]

T = √[ 4π² [( r1 + r2 )³ / 8GM ] ]

T = 2π √[( r1 + r2 )³ / 8GM ]

Therefore, the relation between the time period of the planet is

T = 2π √[( r1 + r2 )³ / 8GM ]

5 0
3 years ago
Someone help! (i will give u a thanks)
soldier1979 [14.2K]

Answer:

a drummer practicing his drum set

Explanation:

8 0
3 years ago
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What is the deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h? (such deceleration caused on
Wewaii [24]

The deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h is  252.52\ m/s^2.

The acceleration in opposite direction is known as the deceleration. Basically the deceleration is negative value of the acceleration since the negative sign depicts its opposite in direction.

The given data:

time, t = 1.1 s

initial speed, u = 1000 km/h = \frac{2500}{9}\ m/s

final speed, v = 0 m/s

So we will be using the equation of motion, that is,

v = u + at

\therefore 0=\frac{2500}{9} + a(1.1)

\Rightarrow a=-\frac{2500}{9(1.1)}

\therefore a = - 252.52 \ m/s^2

Hence , the deceleration of the rocket is  252.52\ m/s^2.

To learn more about Attention here:

brainly.com/question/28500124

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6 0
2 years ago
Suppose that a charged particle of diameter 1.00 micrometer moves with constant speed in an electric field of magnitude 1.00×105
Gnesinka [82]

Answer:

Q1 = 7.25*10^(-16) C 

Explanation:

We are given;

electric field strength = (1 x 10^5 N/C

drag force (F) = 7.25 x 10^(-11) N

The question says it's moving with constant velocity. This means that he particle is in equilibrium and not accelerating.

Columbs law force of attraction or repulsion between two charges is given as;

F=(KQ1Q2)/r²

Now, electric field strength is given as the formula;(K*Q2)/r², thus plugging the relevant values gives us;

7.25 x 10^(-11) N= (1 x 10^(5) N/C)Q1 Q1 = 7.25 x 10^(-11) /(1 x 10^(5))

Q1 = 7.25*10^(-16) C 

5 0
3 years ago
Read 2 more answers
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