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sweet [91]
3 years ago
12

An electron moving horizontally enters a redion whre a constant manetic fiedld B exists posinit upward. What is tge direction of

the force on the electrons when it has entered the feild?

Physics
1 answer:
Snezhnost [94]3 years ago
5 0

Answer:

Down the plane

Explanation:

  • Consider an electron moving left to right in horizontal direction enters a region of a constant magnetic field B which points in the upward direction is acted upon by a force having direction into the plane of the screen which is in accordance to the Fleming's left hand rule.
  • When the left palm extends thumb, middle finger and the index finger mutually perpendicular to each other then the index finger represents the direction of magnetic field. Middle finger represents the direction of motion of a positive charge (assume reverse if the charge is negative) and the thumb represents the direction of force acting on the charge.

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On December 26, 2004, a great earthquake occurred off the coast of Sumatra and triggered immense waves (tsunami) that killed som
k0ka [10]

Answers:

a) 222.22 m/s

b) 800.00 km/h

Explanation:

The speed of a wave is given by the following equation:

v=f \lambda

Where:

v is the speed

f=\frac{1}{T} is the frequency, which has an inverse relation with the period T=1 h

\lambda=800 km is the wavelength

Solving with the given units:

v=\frac{1}{T}\lambda

v=\frac{1}{1 h}800 km

v=800.00 km/h This is the speed of the wave in km/h

Transforming this speed to m/s:

v=800.00 \frac{km}{h} \frac{1 h}{3600 s} \frac{1000 m}{1 km}

v=222.22 m/s This is the speed of the wave in m/s

5 0
3 years ago
The following situation will be used for the next three problems: A rock is projected upward from the surface of the moon, at ti
chubhunter [2.5K]

Explanation:

Given that,

Initial speed of the rock, u = 30 m/s

The acceleration due to gravity at the surface of the moon is 1.62 m/s².

We need to find the time when the rock is ascending at a height of 180 m.

The rock is projected from the surface of the moon. The equation of motion in this case is given by :

h=ut-\dfrac{1}{2}gt^2\\\\180=30t-\dfrac{1}{2}\times 1.62t^2

It is a quadratic equation, after solving whose solution is given by:

t = 7.53 s

or

t = 8 seconds

(e)If it is decending, v = -20 m/s

Now t' is the time of descending. So,

v=-u+gt\\\\t=\dfrac{v+u}{g}\\\\t=\dfrac{20+30}{1.62}\\\\t=30.86\ s

Let h' is the height of the rock at this time. So,

h'=ut-\dfrac{1}{2}gt^2\\\\h'=30\times 30.86-\dfrac{1}{2}\times 1.62\times 30.86^2\\\\h'=154.40\ m

or

h' = 155 m

6 0
3 years ago
I have a voltage source of 12V but a light that only burns at 5V. The lamp works on 18 mA. Calculate the resistance that you EXT
Gala2k [10]

Answer:

The resistance that will provide this potential drop is 388.89 ohms.

Explanation:

Given;

Voltage source, E = 12 V

Voltage rating of the lamp, V = 5 V

Current through the lamp, I = 18 mA

Extra voltage or potential drop = 12 V - 5 V = 7 V

The resistance that will provide this potential drop (7 V) is calculated as follows:

R = \frac{V}{I} = \frac{7 \ V}{18 \times 10^{-3} A} \ = 388.89 \ ohms

Therefore, the resistance that will provide this potential drop is 388.89 ohms.

5 0
3 years ago
A vertically hung spring has a spring constant of 150. newtons per meter. A
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What fraction of stipend triangle is a shaded triangle? What fraction of the spotted triangle is a shaded triangle? Use >,
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4 years ago
A heavy bank-vault door is opened by the application of a force of 300 N directed perpendicular to the plane of the door at a di
kondaur [170]
The answer is 240 Nm.
5 0
3 years ago
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