An electron moving horizontally enters a redion whre a constant manetic fiedld B exists posinit upward. What is tge direction of
the force on the electrons when it has entered the feild?
1 answer:
Answer:
Down the plane
Explanation:
- Consider an electron moving left to right in horizontal direction enters a region of a constant magnetic field B which points in the upward direction is acted upon by a force having direction into the plane of the screen which is in accordance to the Fleming's left hand rule.
- When the left palm extends thumb, middle finger and the index finger mutually perpendicular to each other then the index finger represents the direction of magnetic field. Middle finger represents the direction of motion of a positive charge (assume reverse if the charge is negative) and the thumb represents the direction of force acting on the charge.
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Answer:
Explanation:
Given,
For the first rocket,
- Initial velocity of the first rocket A =
- Acceleration of the first rocket =
For the second rocket,
- Initial velocity of the second rocket B =
- Displacement of both the rockets A and B = s = 0 m
Fro the first rocket,
Let 't' be the time taken by the first rocket A for whole the displacement
Let be the acceleration of the second rocket B for the same time interval
from the kinematics,
Hence the acceleration of the second rocket B is -33.65\ m/s^2.
Answer:
The value of the time constant is 558.11 sec.
Explanation:
Given that,
Pendulum length = 1 m
Initial angle = 15°
Time = 1000 s
Reduced amplitude = 2.5°
We need to calculate the value of the time constant
Using formula of damping oscillation
Where, =amplitude
=amplitude at t = 0
Put the value into the formula
Hence, The value of the time constant is 558.11 sec.