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slava [35]
3 years ago
6

Please help need answer asp

Physics
1 answer:
denis-greek [22]3 years ago
3 0
That is force.  Whenever you see the words push or pull always think of Force
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When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 0.120 m. The mass is now displ
AURORKA [14]

Answer:

Time period of the oscillation will be 0.695 sec

Explanation:

We have given mass attached to the string m = 0.350 kg

The spring is stretched by 0.120 m

So x = 0.120 m

We know that force is given by F = Kx

So mg = kx

0.350\times 9.8=k\times 0.120

k = 28.5833

Now time period is given by

T=2\pi \sqrt{\frac{m}{k}}=2\times 3.14\sqrt{\frac{0.35}{28.5833}}=0.695sec

So time period of the oscillation will be 0.695 sec

6 0
3 years ago
What is the most abundant gas in the atmosphere?
Snowcat [4.5K]

Answer: Nitrogen

Explanation: Nitrogen makes up 78% of the atmosphere, Oxygen makes up 21%, and Argon 0.9%.

Water vaper makes up between 1-4%, depending on the region.

Carbon Dioxide makes up only about 0.04%.

8 0
3 years ago
What will be the ME of a machine that produces a 240 N work with a 300
Elden [556K]

Answer:

Efficiency = 80%

Explanation:

Given the following data;

Work output = 240 N

Work Input = 300 N

To find the mechanical efficiency of a machine;

Efficiency = \frac {Out-put \; work}{In-put \; work} * 100

Substituting into the equation, we have;

Efficiency = \frac {240}{300} * 100

Efficiency = 0.8 * 100

Efficiency = 80%

Therefore, the mechanical efficiency of the machine is 80 percent.

3 0
3 years ago
A 45.5-turn circular coil of radius 4.85 cm can be oriented in any direction in a uniform magnetic field having a magnitude of 0
il63 [147K]

Answer:

4.399 Nm

Explanation:

The maximum Torque on a coil is given as,

τ = BNIA...................... Equation 1

Where τ = Maximum torque exerted on the coil, B = Magnetic Field, N = Number of turns, I = Current, A = Area.

Given: N = 45.5 Turns, B = 0.49 T, I = 26.7 mA = 0.0267 A,

A = πr², Where r = radius of the coil, r= 4.85 cm = 0.0485 m

A = 3.14(0.0485)²

A = 7.39×10⁻³ m².

Substitute into equation 1

τ  = 45.5×0.49×26.7×7.39×10⁻³

τ = 4.399 Nm

3 0
3 years ago
Read 2 more answers
The heating element of a water heater in an apartment building has a maximum power output of 37 kW. Four residents of the buildi
kkurt [141]

Answer:

maximum possible temperature is 34.088°C

Explanation:

Given data

power output Q = 37 kW

volume flow rate = 11 x 10^-5 m3/s

temperature t = 14°C

to find out

maximum possible temperature T

solution

we can say

total water volume  = 4 residents  × volume flow

total water volume = 4 × 11 x 10^-5  = 44 × 10^-5 m³/s

so we say total water mass = 1000 × volume

total water mass = 1000 kg/m³ ×  44 × 10^-5  

total water mass = 0.44 kg

we know

dQ/dt = (dm/dt)× (S)× ( T - t)

so here we know specific heat of water S = 4.186 joule/gram °C

37 = 0.44 × 4.186 × (T-14)

T = 34.088°C

maximum possible temperature is 34.088°C

3 0
3 years ago
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