Answer:
(a) Bus will traveled further a distance of 40 m 
(b) It will take 7.5 sec to stop the bus 
Explanation:
We have given initial velocity of the bus u = 24 m/sec
And final velocity v = 16 m/sec 
Distance traveled in this process s = 50 m 
From third equation of motion we know that 


(a) Now as the bus finally stops so final velocity v = 0 m/sec
So 

s= 90 m 
So further distance traveled by bus = 90-50 =40 m
(b) Now as the bus finally stops so final velocity v= 0 m/sec
Initial velocity u = 24 m/sec
Acceleration 
So time 
 
        
             
        
        
        
Answer:
(a). The charge on the outer surface is −2.43 μC.
(b). The charge on the inner surface is 4.00 μC.
(c). The electric field outside the shell is 
Explanation:
Given that,
Charge q₁ = -4.00 μC
Inner radius = 3.13 m
Outer radius = 4.13 cm
Net charge q₂ = -6.43 μC
We need to calculate the charge on the outer surface
Using formula of charge



The charge on the inner surface is q.


We need to calculate the electric field outside the shell
Using formula of electric field

Put the value into the formula



Hence, (a). The charge on the outer surface is −2.43 μC.
(b). The charge on the inner surface is 4.00 μC.
(c). The electric field outside the shell is 
 
        
             
        
        
        
Answer:
three point charge positioned one x-axis if the charge and corresponding positions are +32Mc x=0 +20Mc x=40cm - 60Mc x=60cm find force 32Mc
Explanation:
 
        
             
        
        
        
Answer:
D
Explanation:
<em>The correct answer would be in the axle of the wheels while you ride your bicycle.</em>
Options A, B, and C requires that the forces of friction is increased in order to have more control.
However, option D requires that there is a minimal frictional force in the axle of the wheels of a bicycle while riding so that a little effort would be required to keep the bicycle moving. 
<u>The lesser the friction, the lower the effort that would be needed to keep the bicycle moving and vice versa.</u>
 
        
             
        
        
        
Answer:
248
Explanation:
L = Inductance of the slinky = 130 μH = 130 x 10⁻⁶ H 
 = length of the slinky = 3 m
 = length of the slinky = 3 m 
N = number of turns in the slinky 
r = radius of slinky = 4 cm = 0.04 m 
Area of slinky is given as 
A = πr²
A = (3.14) (0.04)²
A = 0.005024 m²
Inductance is given as 


N = 248