Answer:
Step-by-step explanation:
............................................ (1)
............................................ (2)
now equate both (1) and (2)
now substitute the values of x ,
when , y becomes 0
when , y becomes 8
so, solution set:
and
Answer:
0.20 and 0.36
Step-by-step explanation:
y(t) = 2 sin (4π t) + 5 cos (4π t)
We wish to convert this to:
y = A sin(ωt + φ)
We know that ω = 4π. We also know the following:
5 = A sin φ
2 = A cos φ
Divide the first equation by the second equation:
5/2 = tan φ
φ = tan⁻¹(5/2)
Now, square the two equations and add them together.
5² + 2² = (A sin φ)² + (A cos φ)²
29 = A²
A = √29
The equation of the wave is therefore:
y = √29 sin(4π t + tan⁻¹(5/2))
The maximum negative position is -√29. And half of that is -½√29.
-½√29 = √29 sin(4π t + tan⁻¹(5/2))
-½ = sin(4π t + tan⁻¹(5/2))
7π/6 + 2kπ or 11π/6 + 2kπ = 4π t + tan⁻¹(5/2)
7 + 12k or 11 + 12k = 24t + 6 tan⁻¹(5/2) / π
t = (7 + 12k − 6 tan⁻¹(5/2) / π) / 24 or (11 + 12k − 6 tan⁻¹(5/2) / π) / 24
Trying different integer values of k, we find there are two possible values for t between 0 and 0.5, both when k = 0.
t = (7 − 6 tan⁻¹(5/2) / π) / 24 or (11 − 6 tan⁻¹(5/2) / π) / 24
t ≈ 0.20 or 0.36
Answer:
So, the required width of rectangular piece of aluminium is 8 inches
Step-by-step explanation:
We are given:
Perimeter of rectangular piece of aluminium = 62 inches
Let width of rectangular piece of aluminium = w
and length of rectangular piece of aluminium = w+15
We need to find width i.e value of x
The formula for finding perimeter of rectangle is:
Now, Putting values in formula for finding Width w:
After solving we get the width of rectangular piece :w = 8
So, the required width of rectangular piece of aluminium is 8 inches