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3 years ago

Find f(2) if f(x)=2x+1 hey besties

Mathematics

1 answer:

Gala2k [10]3 years ago

7 0

Answer: 5

Step-by-step explanation:

f(x)=2x+1

f(2)=2(2)+1 Subtitube 2 for x

f(2)=4+1

f(2)=5

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Correct I’ll give brainlist no links or I’ll report

Elenna [48]

Since he started with Nothing

He had zero initially

After x Months...

He'll have 10x naxvips

in slope intercept form

y=10x

To get the y values ... substitute the corresponding x value

For x=0

y=10(0)

y=0. Which is true cos he had no naxvip initially

x=1

y=10(1)

=10. Which is true cos he buys 10 more monthly... So 10 + 0 = 10.

x=2

y=10(2) = 20. This is true cos he added an additional 10 after each month

x=7

y=70.

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3 years ago

Amir wants to buy a new MP3 player that costs $76.50. If he saves $8.50 each week, how many weeks will it take Amir to save enou

Marat540 [252]

After nine weeks Amir would have enough to buy the MP3

8 0

3 years ago

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Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI

cricket20 [7]

Answer:

The system has infinitely many solutions

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

Switch any two rows
Multiply a row by a nonzero constant
Add one row to another

To solve the following system

$\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}$

Step 1: Transform the augmented matrix to the reduced row echelon form

$\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]$

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

which corresponds to the system

$\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}$

The system has infinitely many solutions.

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

7 0

3 years ago

How do u do this? HELPPPPPPPPPPPP

qaws [65]

You would multiply the like (or similar) terms together.

2*4= 8

-5i*7i= -35i

The correct answer is "A".

I hope this helped you.

Brainliest answer is always appreciated.

8 0

3 years ago

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14,37,60,83,.... What's the rest of the patern?

Ira Lisetskai [31]

106, 129, 152, 175, 198 count by 23

6 0

3 years ago

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