MO = 12 and PR = 3
Solution:
Given 
.
Perimeter of ΔMNO = 48
Perimeter of ΔPQR = 12
MO = 12x and PR = x + 2
<em>If two triangles are similar, then the ratio of corresponding sides is equal to the ratio of perimeter of the triangles.</em>
Do cross multiplication.
Subtract 48x from both sides.
Divide by 96 on both sides, we get
⇒ 1 = x
⇒ x = 1
Substitute x = 1 in MO an PR.
MO = 12(1) = 12
PR = 1 + 2 = 3
Therefore MO = 12 and PR = 3.
You would first have to find common denominators for the fractions. In this case it would be 10. So your new equation would be 3 5/10 - 2 4/10. Once you do this you can then subtract and solve getting the answer of 1 1/10
Answer:
m∠A = 139°
Step-by-step explanation:
First we must know that
Supplementary angles equal to 180 degree.
Since we know that supplementary angles equal to 180 degree we can solve now:
Putting m ∠A and m ∠ B together and put the = 180
( 7x - 15 ) + ( 2x - 3 ) = 180
Now solving for x:
( 7x - 15 ) + ( 2x - 3 ) = 180
9x - 18 = 180
9x - 18 + 18 = 180 + 18
9x = 198
9x/9 = 198/9
x = 22
Hence, Angle A will have a measure of 7x - 15 which means 7 × 22 -15 = 154 - 15 = 139°
m∠A = 139°
The measure of Angle B will be 2x - 3 = 2 • 22 - 3 = 44 - 3 = 41°
m∠ B = 41°
139 + 31= 180
<u><em>[RevyBreeze]</em></u>
Answer:
8.7
Step-by-step explanation:
If you like my answer mark me brainliest
A={x|x is an even while number between 0 and 2} = ∅ since there is no number between 0 and 2 that is an even whole number. So there is no number to be substituted for x, resulting in an empty set.
Hope that helps!
