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MrMuchimi
3 years ago
6

Fill in the blanks to make each equation true.

Mathematics
2 answers:
maks197457 [2]3 years ago
7 0
The answer is that all of them are true
n200080 [17]3 years ago
6 0

Answer: all true

Step-by-step explanation:

Look at the picture closely ull see it

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5.75

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3 years ago
What is the value of x
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2 years ago
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Lia must work at least 5 hours per week in her family’s restaurant for $8 per hour. She also does yard work for $12 per hour. Li
Fittoniya [83]

Answer:

(a)

r\geq  5

r+y\leq 15

8r+12y\geq 120

y\geq 0

(c)Maximum number of hours Lia can work at the restaurant and still meet her earnings goal = 15 hours

(d)Maximum Earning = $160

Step-by-step explanation:

Let r be the number of hours worked at the restaurant.

Let y be the number of hours of yard work,

Lia must work at least 5 hours per week in her family’s restaurant for $8 per hour.

r\geq  5

Since she does yard work, y\geq 0

Lia’s parents allow her to work a maximum of 15 hours per week overall.

r+y\leq 15

Lia’s goal is to earn at least $120 per week.

The restaurant, r pays $8 per hour

Yard work, y pays $12 per hour.

Therefore:

8r+12y\geq 120

The system of inequalities that represent this problem is therefore:

r\geq  5

r+y\leq 15

8r+12y\geq 120

y\geq 0

(b)The graph of the inequality is attached below

(c)When the graph is plotted, the vertices of the feasible region are:

  • (5,10)
  • (5, 6.7)
  • (15,0)

Where the first term is for the number of hours worked in the restaurant.

The maximum value of r possible is 15 from the three points.

Therefore, she can work at the restaurant for 15 hours and still meet her earning goal.

(d)Maximum Amount Lia can earn in 1 Week

  • At (5,10), Earning=(5X8)+(10X12)=40+120=$160
  • At (5, 6.7), Earning=(5X8)+(6.7X12)=40+80.4=$120.4
  • At (15,0) Earning=(15X8)+(0X12)=$120

Since she has to work at least 5 hours at the restaurant, the maximum amount possible is $160.

8 0
3 years ago
Given any two numbers, which is greater, the lowest common multiple of the numbers or the greatest common multiple?
tester [92]

After you've calculated a least common multiple, always check to be sure your answer can be divided evenly by both numbers. Find the LCM of these sets of numbers. Multiply each factor the greatest number of times it occurs in any of the numbers. 9 has two 3's, and 21 has one 7, so we multiply 3 two times, and 7 once.

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Can someione help me with atoms?????
vampirchik [111]

Answer: The first one

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