1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergij07 [2.7K]
3 years ago
7

1 3/4 x 1 1/3 give your answer as a mixed number

Mathematics
2 answers:
dedylja [7]3 years ago
5 0

Answer:

2 1/3

Step-by-step explanation:

WARRIOR [948]3 years ago
4 0

Answer:

2 1/3

Step-by-step explanation:

1 3/4  is equivalent to 7/4

1 1/3 is equivalent to 4/3

7/ 4 x 4/3

reduce with greatest common factor so the two 4 are out (show a line crossing out the top and bottom 4 )

now you're left with 7 x 1/3 = 7/3

7/3 = 2 1/3

You might be interested in
Choose the correct set of y-values for the function y = -2x when x = -2, 0, 2.
kvv77 [185]
The first one
y=-2(-2)=4
y=-2(0)=0
3 0
3 years ago
In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70
Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that P(A) = 0.77

74% of student are taking an English class

This means that P(B) = 0.74

70% of students are taking both

This means that P(A \cap B) = 0.7

Find the probability that a randomly selected student is taking a math class or an English class.

This is P(A \cup B), which is given by:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

1 - P(A \cup B) = 1 - 0.81 = 0.19

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0
3 years ago
X = –16 or x = –4 x = –10 x = –8 x = 4 or x = 16
OverLord2011 [107]
X is 16 so turn everything into a equation
3 0
4 years ago
What do think yall getting for Christmas or tell me what do you want for Christmas?
valentina_108 [34]

Answer:

I want LEGO sets

4 0
3 years ago
Read 2 more answers
Please simplify, 50 points.<br><br> (sin Θ - cos Θ) - (sin Θ + cos Θ)^2
Amanda [17]

Answer:

 

Using x for Θ:  

(sinx - cosx)^2 - (sinx + cosx)^2  

= (sin^2 x - 2sinxcosx + cos^2 x) - (sin^2 x + 2sinxcosx + cos^2 x)  

= - 2 sinx cosx - 2 sinx cosx  

= - 4 sinx cosx  

= - 2sin(2x)  

Step-by-step explanation:

8 0
3 years ago
Other questions:
  • You are going to buy doughnuts for your co workers. You buy 2 boxes of glazed doughnuts for $3.99 each 3 boxes of choclate cover
    8·1 answer
  • Luke ate a snack with 91 total calories. If the chips he ate were 41.2
    13·2 answers
  • 8:20 am to 4:20 pm how many hours and minutes are there?
    15·2 answers
  • Please solve this quickly !
    12·1 answer
  • A community college in Hawaii has a student-to-faculty ratio of 14 to 1. How many faculty members are at the college if it has 4
    5·1 answer
  • Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
    14·1 answer
  • Caleb and Sergio stacked boxes on a shelf. Caleb lifted 14 boxes and Sergio lifted 12 boxes. The boxes that Sergio lifted each w
    12·1 answer
  • A) Model this situation with a linear system:
    9·1 answer
  • The ratio of boys to girls in a class is 5:4. There are 36 students in the class. How many
    10·2 answers
  • What is the least 6 digit multiple of 4 that has all different numbers?
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!