Answer:
The bottom right (v shaped one) is a function
Step-by-step explanation:
Hope this helps:)
Answer:
![8.182X10^8 $pounds](https://tex.z-dn.net/?f=8.182X10%5E8%20%24pounds)
a=8.182 and b=8
Step-by-step explanation:
Weight of the Empire State Building =
pounds.
Weight of the One World Trade Center building= 88,200,000 pounds.
=![8.82 X 10^7](https://tex.z-dn.net/?f=8.82%20X%2010%5E7)
The addition of the two:
![=7.3X 10^8+8.82 X 10^7\\$To make it easier to add, express both as powers of 8\\=7.3X 10^8+0.882 X 10^8\\=(7.3+0.882)X10^8\\=8.182X10^8 $ pounds](https://tex.z-dn.net/?f=%3D7.3X%2010%5E8%2B8.82%20X%2010%5E7%5C%5C%24To%20make%20it%20easier%20to%20add%2C%20express%20both%20as%20powers%20of%208%5C%5C%3D7.3X%2010%5E8%2B0.882%20X%2010%5E8%5C%5C%3D%287.3%2B0.882%29X10%5E8%5C%5C%3D8.182X10%5E8%20%24%20pounds)
Comparing with the form: ![aX10^b](https://tex.z-dn.net/?f=aX10%5Eb)
a=8.182 and b=8
Answer:
The 38th term of 459,450,441,.. will be:
![a_{13}=351](https://tex.z-dn.net/?f=a_%7B13%7D%3D351)
Step-by-step explanation:
Given the sequence
![459,450,441,..](https://tex.z-dn.net/?f=459%2C450%2C441%2C..)
An arithmetic sequence has a constant difference 'd' and is defined by
![a_n=a_1+\left(n-1\right)d](https://tex.z-dn.net/?f=a_n%3Da_1%2B%5Cleft%28n-1%5Cright%29d)
computing the differences of all the adjacent terms
![450-459=-9,\:\quad \:441-450=-9](https://tex.z-dn.net/?f=450-459%3D-9%2C%5C%3A%5Cquad%20%5C%3A441-450%3D-9)
so
![d=-9](https://tex.z-dn.net/?f=d%3D-9)
The first element of the sequence is
![a_1=459](https://tex.z-dn.net/?f=a_1%3D459)
so the nth term will be
![a_n=-9\left(n-1\right)+459](https://tex.z-dn.net/?f=a_n%3D-9%5Cleft%28n-1%5Cright%29%2B459)
![a_n=-9n+468](https://tex.z-dn.net/?f=a_n%3D-9n%2B468)
Putting n=38 to find the 38th term
![a_n=-9n+468](https://tex.z-dn.net/?f=a_n%3D-9n%2B468)
![a_{13}=-9\left(13\right)+468](https://tex.z-dn.net/?f=a_%7B13%7D%3D-9%5Cleft%2813%5Cright%29%2B468)
![a_{13}=-117+468](https://tex.z-dn.net/?f=a_%7B13%7D%3D-117%2B468)
![a_{13}=351](https://tex.z-dn.net/?f=a_%7B13%7D%3D351)
Therefore, the 38th term of 459,450,441,.. will be:
![a_{13}=351](https://tex.z-dn.net/?f=a_%7B13%7D%3D351)
Answer:
![Percent = \frac{100a}{b}\%](https://tex.z-dn.net/?f=Percent%20%3D%20%5Cfrac%7B100a%7D%7Bb%7D%5C%25)
Step-by-step explanation:
Given
![\frac{a}{b}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%7D%7Bb%7D)
Required
Convert to fraction
To do this, we simply multiply the fraction by 100%
This gives:
![Percent = \frac{a}{b} * 100\%](https://tex.z-dn.net/?f=Percent%20%3D%20%5Cfrac%7Ba%7D%7Bb%7D%20%2A%20100%5C%25)
![Percent = \frac{a * 100}{b}\%](https://tex.z-dn.net/?f=Percent%20%3D%20%5Cfrac%7Ba%20%2A%20100%7D%7Bb%7D%5C%25)
![Percent = \frac{100a}{b}\%](https://tex.z-dn.net/?f=Percent%20%3D%20%5Cfrac%7B100a%7D%7Bb%7D%5C%25)
The expression cannot be further simplified.
Take for instance the fraction is: ![\frac{2}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D)
Using the same analysis, the percentage would be:
![Percent = \frac{2}{5} * 100\%](https://tex.z-dn.net/?f=Percent%20%3D%20%5Cfrac%7B2%7D%7B5%7D%20%2A%20100%5C%25)
![Percent = \frac{2 * 100}{5}\%](https://tex.z-dn.net/?f=Percent%20%3D%20%5Cfrac%7B2%20%2A%20100%7D%7B5%7D%5C%25)
![Percent = \frac{200}{5}\%](https://tex.z-dn.net/?f=Percent%20%3D%20%5Cfrac%7B200%7D%7B5%7D%5C%25)
![Percent = 40\%](https://tex.z-dn.net/?f=Percent%20%3D%2040%5C%25)