Answer:
B: 13000 m²
Step-by-step explanation:
To find how much wood is used, we will have to find the surface area of the wooden building.
Formula for surface area of a rectangular pyramid is;
SA = lw + l√(h² + w²/4) + w√(h² + l²/4)
We are given;
l = 100 m
w = 50 m
h = 40 m
Thus;
SA = (100 × 50) + 100√(40² + 50²/4) + 50√(40² + 100²/4)
SA = 5000 + 4717 + 3201.56
SA = 12918.56
Approximating to 2 significant figures gives;
SA = 13000 m²
First square box= 12
Box below 12= 2
Box below 6= 2
SECOND QUESTION
First square box= 15
Circle below 10=5
Circle below 15= 5
HCF= 30
Hope It Helped :D
Answer:
Data Set 1 and 3.
Step-by-step explanation:
For a table to be a function, there cannot be multiple x values of the same number. This means that a function must be one-to-one.
When looking at the data sets, we can eliminate them by using this logic. Data Set 2 contains two y values at y = 6, as well as two x values at x = 1. Therefore, this is not a function.
Data Set 1 is the only table that represents a function because it consists of different x values without any repeating.
Data Set 3 also contains different x values without repetition. Each x value has a specific y value. This is a function as well.
Answer is 50
Reason
Using Pythagorean theory
a^2 + b^2 = c^2
a and b are the legs, the hypotenuse is c
14^2 + 48^2 = c^2
2500 = c^2
Now take the square root of both sides
50 = c
We know that, as per a corollary of intermediate value theorem, if a function f(x) is continuous on a closed interval [a,b], and values of f(a) and f(b) have opposite signs, then the function f(x) is guaranteed to have a zero on the interval (a,b).
So, basically, we need to figure out two values of x, at which the values of the given cubic function have opposite signs.
Let us consider the interval [-2,1].
We have . Upon substituting the values x=-2 and x=1 one by one, we get:
We can see that signs of values of the function at x=-2 and x=1 are opposite, therefore, as per intermediate value theorem, the function is guaranteed to have a zero on the interval [-2,1]