All categories

3 years ago

Helppppppppppp plzzz

Mathematics

1 answer:

Basile [38]3 years ago

8 0

Answer:

Step-by-step explanation:

hope this helps......

You might be interested in

How do I solve this ?

Alja [10]

Answer:

g(-9) = 1

Step-by-step explanation:

g(-9) is the value of the function at x = -9

Go over the x = -9 and go up until you hit the blue line

Read the value of y

g(-9) = 1

5 0

3 years ago

Read 2 more answers

Find the value of x when m<2 = x + 64

polet [3.4K]

Answer:

-9

Step-by-step explanation:

The triangle has two sides that are the same, so it is an isosceles triangle. Therefore, the base angles are the same.

Angles of a triangle add up to 180°, so:

70 + (x + 64) + (x + 64) = 180

70 + 2x + 128 = 180

2x = -18

x = -9

5 0

3 years ago

Read 2 more answers

The graph shows the calling charges of two cell phone companies. At how many minutes do the two companies charge the same amount

vaieri [72.5K]

Answer:

the correct answer would be c. 20 minuets

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

A fisherman positions his net to -8 relative to the surface of the water. how far does he need to raise the net to bring it to t

8_murik_8 [283]

Answer: If i am correct the answer should be 9-10 because if it is -8 it takes 8 to bring it to 0 and it takes 9 to bring it to 1 and it takes 10 to bring it to 2.

Hope this helps!

6 0

3 years ago

Helppppppppppp plzzz ​

Helppppppppppp plzzz