The function notation of the following are:
f(1) = 5
f(0) = 1
f(-3) = -11
f(8) = 33
Given:
x is the input.
the function is 4x+1
f(x) is the output.
we are asked to determine the values of the following :
a. f(1)
x = 1
so f(x) = 4x+1
f(1) = 4(1)+1
f(1) = 4+1
f(1)=5
b. f(0)
x = 0
so f(x) = 4x+1
f(0) = 4(0)+1
f(0) = 0+1
f(0)=1
c. f(-3)
x = -3
so f(x) = 4x+1
f(-3) = 4(-3)+1
f(1) = -12+1
f(1)= -11
d. f(8)
x = 8
so f(x) = 4x+1
f(8) = 4(8)+1
f(8) = 32+1
f(1)=33
Hence we get the required values.
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Answer:
m∠2=35°, m∠1=35°
Step-by-step explanation:
∠2 and ∠4 equal 180° when added, so 180-145=35
all angles of a triangle equal 180°, so 180-∠3-∠2=∠1
180-110-35= 35
Estimation is a important skill to know when adding and subtracting decimals because if you estimate you have an idea on what your answer should be close to.
For example 4.68-2.38 could be 5-2 which is 3. 4.68-2.38 equals 2.3. 2.3 is close to 3.
Answer: a) 2:1. b) 3. c) Perimeter of ΔEFG=36 Perimeter of ΔHIJ=18. d) 2:1
Step-by-step explanation:
a) Find the ratio of GF and JI. 16:8. Simplify by dividing both by 8 to get 2:1.
b) Set up this equation: 6/16=x/8. Cross-multiply. 6*8=48. Divide by 16. 48/16=3.
c) First find the length of one half of GF by dividing 16 by 2. 16/2=8. Set up the Pythagorean theorem. 8^2+6^2=c^2. Square 8 and 6. 64+36=c^2. Add 64 and 36. 100=c^2. Find the square root of 100. c=10.
EF and EG both measure 10 since they are shown to be congruent. 10+10+16=36.
Next find the length of one half of JI by dividing 8 by 2. 8/2=4. Set up the Pythagorean theorem. Since we know x=3, it will be 4^2+3^2=c^2. Square both 4 and 3. 16+9=c^2. Add 16 and 9. 25=c^2. Find the square root of 25. c=5.
HJ and HI both measure 5 since they are congruent. 5+5+8=18.
d) Find the ratio of the perimeters of ΔEFG and ΔHIJ. 36:18. Simplify by dividing both by 6 to get 6:3. Simplify further by dividing both by 3 to get 2:1.
Answer:
B.
Step-by-step explanation:
Every answer besides B. has an input that repeats. A function contains inputs that have exactly one output. This means x values cannot have more than one y value.
