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3 years ago

Michael drove 0.5 miles. How many inches did he travel?

Mathematics

2 answers:

Levart [38]3 years ago

7 0

It would be 31,680 inches

Anvisha [2.4K]3 years ago

4 0

Answer:

31680 inches

Step-by-step explanation:

To find miles to inches, multiply by 63360 to get the answer.

0.5 x 63360 = 31680

So, he traveled 31680 inches.

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72/1000 as a decimal

polet [3.4K]

Answer: 0.072

Explanation: There are 3 zeros in 1000, so there must be 3 decimal digits.

5 0

3 years ago

Read 2 more answers

Shania had $20 to spend on seven raffle tickets. After buying them she had $6. How much did each raffle ticket cost?

kogti [31]

Answer:

Step-by-step explanation:

Total money Shania was having = $20.

After buying raffle tickets she was having a total of $6.

Thus ,

The money she spent on the raffle tickets = Money she was having initially -

Money she was having after

purchasing tickets .

= $20 - $6

= $14.

Thus She spent a total of $14 on tickets .

Now , number of tickets she bought = 7.

So, cost of each ticket = $\frac{Money spent}{Number of tickets}$ = $\frac{14}{7}$

= $2.

Thus , each ticket costs $2 for Shania.

7 0

3 years ago

An Airliner has a capacity for 300 passengers. If the company overbook a flight with 320 passengers, What is the probability tha

TEA [102]

Answer:

The probability is $P(X >300 ) = 0.97219$

Step-by-step explanation:

From the question we are told that

The capacity of an Airliner is k = 300 passengers

The sample size n = 320 passengers

The probability the a randomly selected passenger shows up on to the airport

$p = 0.96$

Generally the mean is mathematically represented as

$\mu = n* p$

=> $\mu = 320 * 0.96$

=> $\mu = 307.2$

Generally the standard deviation is

$\sigma = \sqrt{n * p * (1 -p ) }$

=> $\sigma = \sqrt{320 * 0.96 * (1 -0.96 ) }$

=> $\sigma =3.50$

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

$P(X > k ) = P( \frac{ X -\mu }{\sigma } > \frac{k - \mu}{\sigma } )$

Here $\frac{ X -\mu }{\sigma } =Z (The \ standardized \ value \ of \ X )$

=> $P(X >300 ) = P(Z > \frac{300 - 307.2}{3.50} )$

Now applying continuity correction we have

$P(X >300 ) = P(Z > \frac{[300+0.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )$

=> $P(X >300 ) = P(Z > -1.914 )$

From the z-table

$P(Z > -1.914 ) = 0.97219$

$P(X >300 ) = 0.97219$

8 0

3 years ago

2. Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 1

Yuki888 [10]

The area of the walkway is 168 square feet if Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 12ft.

<h3>What is the area of the rectangle?</h3>

It is defined as the space occupied by the rectangle, which is planner 2-dimensional geometry.

The formula for finding the area of a rectangle is given by:

Area of rectangle = length × width

The dimensions of the garden = 10 ft by 12 ft

Area = 10×12 = 120 square feet

The width of the walkway = 3 feet

If we create a walkway around the garden, it will be a rectangle around the garden.

So the dimensions for the bigger rectangle = (3+10+3) ft by (3+12+3) ft

Area of the bigger rectangle = 16×18 = 288 square feet

So the area of the walkway = 288 - 120 = 168 square feet

Thus, the area of the walkway is 168 square feet if Ms. Rich is creating a walkway around her rectangular garden. If the walkway will be 3 feet wide, and the garden is 10ft by 12ft.

Learn more about the rectangle here:

brainly.com/question/15019502

#SPJ1

4 0

2 years ago

Pls help !!! pleaseee.

ladessa [460]

I guess B. That statement is grammatically incorrect.

8 0

2 years ago