Water and oxygen
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N2 + 3 H2 >> 2 NH3
moles NH3 = 11.50 g /17.0307 g/mol=0.6753
the ratio between H2 and NH3 is 3 : 2
moles H2 needed = 0.6753 x 3/2 =1.013
mass H2 = 1.013 mol x 2.106 g/mol=2.042 g
Answer:
The vapor pressure of ethanol in the solution is 10,27 kPa
Explanation:
To obtain the vapor pressure of a solution it is necessary to use Raoult's law:
<em>(1)</em>
The moles of ethanol are:
18,00mL×
×
= 0,3083 mol Ethanol.
Moles of benzoic acid:
12,55 g×
= 0,1028 mol benzoic acid.
Thus, mole fraction of solvent, X, is:
=<em> 0,7499</em>
Replacing this value in (1):
= <em>10,27 kPa</em>
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I hope it helps!
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