Answer:
1.84g of H₂ are needed to produce 10.42g of NH₃
Explanation:
In the production of ammonia, NH₃, the following reaction occurs
N₂ + 3H₂ ⇄ 2NH₃
From, the above, <em>3 moles</em> of hydrogen gas (H₂) is required to produce <em>2 moles</em> of ammonia (NH₃).
The atomic mass of Hydrogen is <em>1 g/mol</em>, <em>3 moles</em> of hydrogen gas are present in the reactant, hence the mass of hydrogen gas in the equation is;
3 × 2 × 1 = <u>6g</u>
The atomic mass of Nitrogen is <em>14g/mol</em>, that of hydrogen is <em>1g/mol</em> and <em>2 moles</em> of ammonia were produced. Hence the mass of ammonia in the equation is;
(2 × 14) + (2 × 3 × 1) = <u>34g</u>
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From the above, it can be deduced that 6g of H₂ is required to produce 34g of NH₃, hence "x" grams of H₂ are needed to produce 10.42g of NH₃
To find x (which is the unknown)
6g ⇒ 34g
x ⇒ 10.42g
x = 
x = 1.84g
1.84g of H₂ are needed to produce 10.42g of NH₃