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Oksana_A [137]
3 years ago
10

I need help question 7

Chemistry
1 answer:
algol [13]3 years ago
8 0

Answer:

B

Explanation:

As you can see in these 4 examples, B- looks completely different from A, C, D! In B: The reactants and products are completely different in the Element Figures.

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Which equation represents the total ionic equation for the reaction of HNO3 and NaOH? Upper H superscript plus, plus upper O upp
DIA [1.3K]

Answer:

Total Ionic equation:

H⁺(aq) + NO₃⁻ (aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + NO₃⁻ (aq)

Explanation:

Chemical equation:

HNO₃ + NaOH →  NaNO₃ + H₂O

Balanced chemical equation:

HNO₃(aq) + NaOH(aq) →  NaNO₃(aq) + H₂O(l)

Total Ionic equation:

H⁺(aq) + NO₃⁻ (aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + NO₃⁻ (aq)

Net ionic equation:

H⁺(aq) + OH⁻(aq) → H₂O(l)  

The NO₃⁻ (aq)  and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation

6 0
3 years ago
Read 2 more answers
Your bedroom air conditioner blows very cold air at night but only cool air during the day. Your bedroom gets lots of direct sun
malfutka [58]

What is the experiment

8 0
3 years ago
Which statement is best described as a atom
myrzilka [38]

a core of protons and neutrons surrounds by electrons

6 0
3 years ago
Convert 32.56 km/hr into ft/hr
Gekata [30.6K]
Note that
1 m = 3.2808 ft

Therefore
1 km = 3280.8 ft
and
32.56 \,  \frac{km}{h} = (32.56 \,  \frac{km}{h})*(3280.8 \,  \frac{ft}{km}) =  1.0682 \, \times 10^{5} \, \frac{ft}{h}

Answer: 1.0682 x 10⁵ ft/hr

8 0
2 years ago
4. Consider the following half-reactions: MnO4–(aq) + 8H+(aq) + 5e– → Mn+2(aq) + 4H2O(l) NO3–(aq) + 4H+(aq) + 3e– → NO(g) + 2H2O
jeyben [28]

Explanation:

The chemical reaction given in the question is as follows -

MnO₄⁻ (aq) + 8H⁺ (aq) + 5e⁻ → Mn²⁺ (aq) + 4H₂O (l)

NO₃⁻ (aq) + 4H⁺ (aq) + 3e⁻ → NO (g) + 2H₂O (l)

As we know , the value for reduction potential are -

Mn²⁺ = + 1.51  V

NO₃⁻  =  +0.96 V

From , the data given above , the value of the reduction potential of NO₃⁻ is less than the reduction potential of Mn²⁺ .

Hence ,

NO₃⁻  can not oxidize Mn²⁺ .

5 0
2 years ago
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