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Zarrin [17]
3 years ago
15

The perimeter of an equilateral triangle is at most 45 centimeters Find the possible length of each side

Mathematics
1 answer:
Tju [1.3M]3 years ago
3 0

The perimeter is  3  times the length of each side:

p = 3s


If the perimeter is at most  45 cm, then

p ≤ 45 cm

3s ≤ 45 cm

           45 cm
s  ≤  —————
               3


s ≤ 15 cm


So each side is at most  15 cm.


I hope this helps. =)

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shusha [124]

Consider the function G(x) = -2x^3 - 15x^2 + 36x. First, factor it:

G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).

The x-intercepts are at points \left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).

1. From the attached graph you can see that

  • function is positive for x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);
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2. Since

G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x) the function is neither even nor odd.

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8 0
3 years ago
Read 2 more answers
Simplify the expression: <br>3+ – 5(4+ – 3v)
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Answer:

The answer is

<h2>15v - 17</h2>

Step-by-step explanation:

3+ – 5(4+ – 3v) can be written as

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That's

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Hope this helps you

6 0
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Tata Darka ma 20 m siatki ogrodzeniowej.Jakie wymiary w metrach,wyra¿one liczbami naturalnymi,powinien mieæ prostok¹tny warzywni
grin007 [14]

Answer:

Hence the dimensions are 5×5 i.e. 5 meters and 5 meters such that its field would be as large as possible.

Step-by-step explanation:

Darek's dad has a 20 m fencing mesh.

Since we have to make a rectangular garden with he help of fencing the garden using this mesh, that means perimeter of this garden is 20 m.

i.e. 2( l+b)=20

also we have to fenced in such a way that its field would be as large as possible.

ie. it has the largest Area.

Now we will start from the dimensions possible as:

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5 0
2 years ago
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