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Viktor [21]
3 years ago
9

A real number line can represent both real and imaginary numbers True or false ?

Mathematics
2 answers:
fgiga [73]3 years ago
7 0
True is the answer to this question
forsale [732]3 years ago
5 0

Answer:

True

Step-by-step explanation:

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The set of points in space that are a given distance from a given point is called a(n) __________.
Marrrta [24]

The answer would be B. Edge

The set of points in space that are a given distance from a given point is called an <u>Edge.</u>

D would be incorrect since it doesn’t have any edges and is like a circle but is 3D. A cylinder is also incorrect since it has curves from top to bottom. C is also incorrect since it only shows one side, which is called the face. That leaves you with edge which would be the correct answer.


Hope this helps! :3

8 0
3 years ago
Let f be a differentiable function such that f(3)=15, f(6)=3, f ' (3)= -8, and f ' (6)= -2. The function g is differentiable and
Ray Of Light [21]

Answer:

A. g'(3)=-\frac{1}{2}

Step-by-step explanation:

We have been given that f be a differentiable function such thatf(3)=15, f(6)=3, f'(3)= -8, and f'(6)= -2. The function g is differentiable and g(x)= f^{-1} (x) for all x.

We know that when one function is inverse of other function, so:

g(f(x))=x

Upon taking derivative of both sides of our equation, we will get:

g'(f(x))*f'(x) =1

g'(f(x))=\frac{1}{f'(x)}

Plugging x=6 into our equation, we will get:

g'(f(6))=\frac{1}{f'(6)}

Since g(x)= f^{-1} (x), then g'(f(6))=g'(3).

g'(3)=\frac{1}{f'(6)}

Since we have been given that f'(6)= -2, so we will get:

g'(3)=\frac{1}{-2}

g'(3)=-\frac{1}{2}

Therefore, g'(3)=-\frac{1}{2} and option A is the correct choice.

8 0
3 years ago
Please help I've been have trouble with it.
kakasveta [241]
It should be Answer D. I hope this helps. I also hope you have a great day!!!
3 0
3 years ago
Read 2 more answers
Identify whether each line is linear, quadratic, or neither
VMariaS [17]
Y=7 is linear
y=3x^2+1/2x-x^3+1 is neither
y=2x+5x^2-1 is quadratic
y=x/(x-1) is neither
y=(x^2+8x-20)/4 is quadratic
y=(x+5)(x-4) is quadratic
5 0
3 years ago
What is the product of 2x(x-4)
aliya0001 [1]

The answer to your question is 2x^2 - 8x

8 0
3 years ago
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