9514 1404 393
Answer:
a) x = -3
b) y = (28/27)x -27
Step-by-step explanation:
a) College street has a slope of 0, so is a horizontal line. 2nd Ave is perpendicular, so is a vertical line, described by an equation of the form ...
x = constant
For 2nd Ave to intersect the point (-3, 1), the constant must match that x-coordinate. The equation is ...
x = -3
__
b) Since Ace Rd is perpendicular to Davidson St, its slope will be the opposite reciprocal of the slope of Davidson St. The slope of Ace Rd is ...
m = -1/(-27/28) = 28/27
Using the point-slope equation for a line, we can model Ace Rd as ...
y -y1 = m(x -x1)
y -1 = (28/27)(x -27)
y = (28/27)x -27
You could write this by going 63+42 or add 63 and 42
hope that's what you are looking for ;-)<span />
Answer:
c
Step-by-step explanation:
its c because I just cacuulated it
8x + By + 92 = 0
(-4; 12) ⇒ x = -4; y = 12
subtitute
8 · (-4) + 12B + 92 = 0
-32 + 12B + 92 = 0
12B + 60 = 0 |subtract 60 from both sides
12B = -60 |divide both sides by 12
B = -5