(3x + 4)³ = 2197
Taking the cube root in this case is easier, although we can do it the extended way which is complicated.
![\sqrt[3]{(3x+4)^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%283x%2B4%29%5E3%7D%20)
=
![\sqrt[3]{2197}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2197%7D%20)
3x + 4 = 13
Now solve normally.
subtract 4
3x + 4 = 13
-4 -4
3x = 9
Divide by 3 to isolate 3

3 and 3 cancels out
x = 3
Answer:
A) (x-7)/(x+4)
Step-by-step explanation:
(x^2-10x+21)/(x^2+x-12)=[(x-3)(x-7)]/[(x+4)(x-3)]=(x-7)/(x+4)
The anwser is (B) hope this helped
Answer:
i believe the answer is B
Step-by-step explanation:
make 2 and 2/3 a decimal
2 divided by 3 will give you .6 repeating. just round to .8
then divide 48 by 2.8
it will give you 17.142
i just rounded it to 18... bc its so close to it
<u>hope this helps :)</u>