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ivanzaharov [21]
2 years ago
7

H=4(x+3y)+2 make x the subject

Mathematics
2 answers:
blagie [28]2 years ago
5 0
H = 4(x + 3y) + 2
H = 4x + 12y + 2
H - 12y - 2 = 4x
(H - 12y - 2) / 4 = x or 1/4H - 3y - 1/2 = x

Radda [10]2 years ago
4 0

Answer:

x=\frac{1}{4}(h-12y-2)

Step-by-step explanation:

We are given the equation h=4(x+3y)+2.

Simplifying for x, we get,

h=4(x+3y)+2

i.e. h=4x+12y+2

i.e. 4x=h-12y-2

i.e. x=\frac{1}{4}(h-12y-2)

<h3>Thus, the equation for x is x=\frac{1}{4}(h-12y-2)</h3>
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A flute is on sale for 20% off. Including the discount and 8% tax, the sales price is $216.
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Is RS perpendicular to DF? Select Yes or No for each statement. R (6, −2), S (−1, 8), D (−1, 11), and F (11 ,4) R (1, 3), S (4,7
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I'll do the first one to get you started.  

Find the slope of the line between R (6,-2) and S (-1,8) to get

m = (y2-y1)/(x2-x1)

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The slope of line RS is -10/7

Next, we find the slope of line DF

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From here, we multiply the two slope values

(slope of RS)*(slope of DF) = (-10/7)*(-7/12)

(slope of RS)*(slope of DF) = (-10*(-7))/(7*12)

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Because the result is not -1, this means we do not have perpendicular lines here. Any pair of perpendicular lines always has their slopes multiply to -1. This is assuming neither line is vertical.

I'll let you do the two other ones. Let me know what you get so I can check your work.

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what is an equation of the line that passes through (3-1) and is parallel to y = -4x + 1 in slope intercept form?
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So we are given that the line passes through (3,-1)
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y = -4x +11

Hope this helps :)
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3 years ago
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