Answer:
The acceptable times are;
a) Between 10:00 PM and 11:00 PM
b) Between 7:30 AM and 9:00 AM
Step-by-step explanation:
From the question, we have that Mark an Hans are not able to c h a t in the times between;
a) 9:00 AM and 4:30 PM
b) 11:00 PM and 7:00 AM
Local times
Therefore they can c h a t at times between;
a) 7:00 AM and 9:00 AM
b) 4:30 PM and 11:00 PM
When the time is 1:00 AM in Berlin, it is 10:00 AM in Sydney
Therefore, the time difference between Sydney, Australia and Berlin, Germany = 10:00 AM - 1:00 AM = 9 hours
Therefore, when Mark can c h a t, the time in Berlin will be;
a) 7:00 AM -09:00 = 10:00 PM and 9:00 AM - 09:00 = 0:00 AM
Which gives;
10:00 PM and 0:00 AM
b) 4:30 PM - 09:00 = 7:30 AM and 11:00 PM - 09:00 = 2:00 PM
7:30 AM and 2:00 PM
Therefore, the acceptable times they can c h a t is found by overlapping the above times at Hans location in Berlin with the times Mark can c-hat in Sydney, Australia to get;
The acceptable times are between;
a) 10:00 PM and 11:00 PM
b) 7:30 AM and 9:00 AM
4.3 should be the correct answer.
So we want to know what is the difference in magnitude of a large quake M(l) and a small quake M(s) in the Richter scale if the amplitude of a large quake A(l) is 1000 times bigger than the amplitude of a small quake A(s) and the formula is M(l)-M(s)=log{A(l)/A(s)}. So the large amplitude is 1000 bigger than the small amplitude: A(l)=1000*A(s). When we insert that into the formula we get:
M(l)-M(s)=log{1000*A(s) / A(s)}, because the A(s) cancel out, so we get:
M(l)-M(s) = log{1000} = 3.
So the difference in magnitude on the Richter scale is M(l)-M(s)=3.
Answer:
Step-by-step explanation:
0.00 round it to 1 place after decimal point.
If the next number >=5, add 1 to the before number. Ex: 5.56 => 5.6.
If the next number < 5, then keep it as normal. Ex: 5.44 => 5.4.