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shutvik [7]
3 years ago
6

A rectangular prism has a top face with an area of 20 ft2 and a height of 5 ft. What is the volume of this rectangular prism? Th

is is a 5th grade Question
Mathematics
1 answer:
kkurt [141]3 years ago
6 0

Answer:

the volume of the rectangular prism is 100 ft³  

Step-by-step explanation:

Given;

area of top face of a rectangular prism, A = 20 ft²

height of the rectangular prism, h = 5 ft

Volume of the rectangular prism =  Area of top face x height of the rectangular prism

Volume of the rectangular prism = A x h

Volume of the rectangular prism = 20 ft² x  5 ft

                                                       = 100 ft³

Therefore, the volume of the rectangular prism is 100 ft³                                      

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viva [34]

The slope-intercept form of a line:

y=mx+b\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\to slope\\\\b\to y-intercept

We have:

(-3,\ 2)\to x_1=-3,\ y_1=2\\(1,\ 5)\to x_2=1,\ y_2=5

Substitute:

m=\dfrac{5-2}{1-(-3)}=\dfrac{3}{4}

y=\dfrac{3}{4}x+b

Put the values of coordinates of the point (1, 5) to the equation of a line:

5=\dfrac{3}{4}(1)+b\\\\5=\dfrac{3}{4}+b\qquad|-\dfrac{3}{4}\\\\b=4\dfrac{1}{4}

Answer: y=\dfrac{3}{4}x+4\dfrac{1}{4}


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3 years ago
2 + 1 . 2 5 f = 1 0 − 2 . 7 5 f
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f=2


7 0
2 years ago
What is the solution to the equation?
ki77a [65]
5(8 + 7) = 5\cdot x + 5 \cdot 7\\
5\cdot15=5x+35\\
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8 0
3 years ago
On a quiet day without many witnesses, a 4.5 ft victim was shot by a sniper that was in a tower 780 ft away. If the angle of ele
azamat

Answer:

68.17m

Step-by-step explanation:

Please see attached a rough sketch of the scenario

Step one:

Given data

Height of victim= 4.5ft

The horizontal distance of the snipper from the building = 780ft

The angle of elevation= 5 degrees

Required

The vertical distance

The opposite= the vertical distance

789 ft = the adjacent

Step two:

Applying SOH CAH TOA

tan ∅= opp/adj

tan 5= opp/780

cross multiply we have

0.0874= opp/780

cross multiply we have

0.0874*780= opp

opp= 68.17m

The sniper shoots from a vertical distance of  68.17m

8 0
2 years ago
In Exercises 23–36, solve the system using either Gaussian elimina- tion with back-substitution or Gauss-Jordan elimination. 23.
Luba_88 [7]

Answer:

23) x= 3, y = 4

24) Any (x,y) values where x = 1.5 - 2y

Step-by-step explanation:

For the first system(23), it goes like this

[1 2 | 7]

[2 1 | 8]

We need to do L2 = L2 - 2L1, so now it is

[1 2   | 7]

[0 -3 |-6]

So, now we have:

-3y = -6 *(-1)

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We do L2 = L2 + 2L1, so we have:

[-1 2 | 1.5]

[0 0| 0]

So there are infinite solutions for this system. The solution for this system will be each (x,y) pair where x = 1.5 - 2y.

5 0
3 years ago
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