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mrs_skeptik [129]
2 years ago
13

Write 63/100 as a decimal

Mathematics
1 answer:
wel2 years ago
5 0

Answer:

it is 0.63

Step-by-step explanation:

plz give me a brainliest plz

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Steve opens a bank account with a simple annual interest rate of 5%. After four years, how much interest will Steve earn on an i
Marysya12 [62]

Steve will earn $160 interest after four years ⇒ 1st answer

Step-by-step explanation:

The formula of the simple interest is I = Prt, where

  • P is the initial deposit
  • r is the annual rate in decimal
  • t is the time of investment

∵ Steve opens a bank account with a simple annual interest rate of 5%

∴ r = 5% = 5 ÷ 100 = 0.05

∵ His initial deposit is $800

∵ He will put the money for four years

∴ t = 4

- Substitute all these values in the formula above

∵ I = 800(0.05)(4)

∴ I = 160

Steve will earn $160 interest after four years

Learn more:

You can learn more about the interest in brainly.com/question/13018049

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
I'm having trouble with #2. I've got it down to the part where it would be the integral of 5cos^3(pheta)/sin(pheta). I'm not sur
Butoxors [25]
\displaystyle\int\frac{\sqrt{25-x^2}}x\,\mathrm dx

Setting x=5\sin\theta, you have \mathrm dx=5\cos\theta\,\mathrm d\theta. Then the integral becomes

\displaystyle\int\frac{\sqrt{25-(5\sin\theta)^2}}{5\sin\theta}5\cos\theta\,\mathrm d\theta
\displaystyle\int\sqrt{25-25\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\sqrt{1-\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta

Now, \sqrt{x^2}=|x| in general. But since we want our substitution x=5\sin\theta to be invertible, we are tacitly assuming that we're working over a restricted domain. In particular, this means \theta=\sin^{-1}\dfrac x5, which implies that \left|\dfrac x5\right|\le1, or equivalently that |\theta|\le\dfrac\pi2. Over this domain, \cos\theta\ge0, so \sqrt{\cos^2\theta}=|\cos\theta|=\cos\theta.

Long story short, this allows us to go from

\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta

to

\displaystyle5\int\cos\theta\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\dfrac{\cos^2\theta}{\sin\theta}\,\mathrm d\theta

Computing the remaining integral isn't difficult. Expand the numerator with the Pythagorean identity to get

\dfrac{\cos^2\theta}{\sin\theta}=\dfrac{1-\sin^2\theta}{\sin\theta}=\csc\theta-\sin\theta

Then integrate term-by-term to get

\displaystyle5\left(\int\csc\theta\,\mathrm d\theta-\int\sin\theta\,\mathrm d\theta\right)
=-5\ln|\csc\theta+\cot\theta|+\cos\theta+C

Now undo the substitution to get the antiderivative back in terms of x.

=-5\ln\left|\csc\left(\sin^{-1}\dfrac x5\right)+\cot\left(\sin^{-1}\dfrac x5\right)\right|+\cos\left(\sin^{-1}\dfrac x5\right)+C

and using basic trigonometric properties (e.g. Pythagorean theorem) this reduces to

=-5\ln\left|\dfrac{5+\sqrt{25-x^2}}x\right|+\sqrt{25-x^2}+C
4 0
2 years ago
Read 2 more answers
Caleb strung a 12 foot rope from the bottom of one fence post to the top of another. He measured the angle of elevation of the r
OLEGan [10]
The answer for this question is b because the angle of elevation of the rope as 35°
5 0
3 years ago
What is the slope and y-intercept of y+3= -1/3
bazaltina [42]

Assuming this is written correctly, with no x in the equation, we just solve for y:

y = -3 - 1/3 = -10/3 = 0 x - 10/3

That's slope-intercept form.

Answer: Slope 0, y-intercept -10/3


5 0
3 years ago
Please help!!! thank you
fiasKO [112]

Answer:

28

Step-by-step explanation:

140 divided by 5 is 28

224 divided by 8 is 28

480 divided by 15 is 28

3 0
3 years ago
Read 2 more answers
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