If the ends span from the 0 to the 15 meter mark, then the length of the pipe is 15 meters. However, you should report it using the right amount of significant figures. It is mentioned in the problem that millimeter marks are calibrated between meters. Since millimeter is 1/1000 of a meter, you should add three decimal places to the 15 meters. Hence, you should report it as 15.000 meters.
So we can call the width of the rectangle x.
So then the length would be 4x.
The perimeter would then be 10x.
Since the perimeter is 70, we can say 70 = 10x.
And then simplify that to 7 = x.
So the length of a rectangle would be 28 cm, and the width would be 7.
So to find the area, just multiply length by width.
28*7 = 196 square cm
So the rectangle's area is 196 square cm.
I hope I helped!
Answer:
The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.
Step-by-step explanation:
Normal variables
Normal variables have mean
and standard deviation 
When we add normal variables, the combined mean is the sum of both means, and the standard deviation is the square root of the sum of both variances. The distribution is still normal.
In this question:
Verbal:
.
Math: 
Combined:


The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.
3/4 w = 9
multiply by 4/3 on both sides
4/3 x 3/4 w = 9 x 4/3
w = 9 x 4/3
Simplify that
w = 3 x 4
w = 12
So your final answer is