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Bess [88]
2 years ago
11

If sin= 7/25 what are the other primary trig ratios?

Mathematics
2 answers:
statuscvo [17]2 years ago
8 0

Answer:

cos=24/25

tan=7/24

Step-by-step explanation:

sin=opposite/hypotenuse

therefore 7 is the opposite and 25 is the hypotenuse.

using pythagorean theorem we can find the adjacent. i.e hypotenuse squared= sum of adjacent squared and opposite squared.

h^2= a^2+ O^2

25 squared - 7 squared= 576

which is equal to 24 squared.

therefore adjacent=24

cos=adjacent/hypotenuse

cos=24/25

tan=opposite/adjacent

tan=7/24.

KonstantinChe [14]2 years ago
6 0

Answer:

\cos(\theta)= \dfrac{24}{25}

\tan(\theta)=\dfrac{7}{24}

Step-by-step explanation:

<h3><u>General outline</u></h3>
  1. Trig ratio Definitions
  2. Visualizing the triangle for the problem
  3. Applying the Pythagorean Theorem
  4. Identifying the other trig ratios

<u />

<h3><u>Step 1. Trig ratio definitions</u></h3>

<u>Definitions of primary trig functions</u>

For a given acute angle in a right triangle :

  • Sine function:  \sin(\theta)=\dfrac{\bold{opposite} \text{ side length}} {\bold{hypotenuse} \text{ length}}
  • Cosine function:  \cos(\theta)=\dfrac{\bold{adjacent} \text{ side length}} {\bold{hypotenuse} \text{ length}}
  • Tangent function:  \tan(\theta)=\dfrac{\bold{opposite} \text{ side length}} {\bold{adjacent} \text{ side length}}

...where the hypotenuse is the side across from the right angle, the opposite side is the side not touching the angle theta, and the adjacent side is the side touching the angle theta (but that isn't the hypotenuse).

We are already given the ratio for the Sine function, so <u>we need to find the Cosine and Tangent function ratios</u>.  It will be helpful to visualize what this triangle looks like.

<h3><u>Step 2. Visualizing the triangle for the problem</u></h3>

The given equation states \sin(\theta)=\frac{7}{25}, so there is some right triangle, with a specific angle theta, that has a ratio of sides (opposite to hypotenuse) of 7 to 25.  <em>For ease, we'll consider the triangle that has actual side lengths of 7 and 25 for those sides.  (See attached diagram)</em>

<em />

Given that information, we can identify that the unknown side length is the adjacent side length.  Since the triangle is a right triangle, this value can be found through the Pythagorean Theorem.

<h3><u>Step 3. The Pythagorean Theorem</u></h3>

The Pythagorean Theorem states that for any right triangle, a^2+b^2=c^2 where "c" is the length of the hypotenuse of the triangle, and "a" and "b" are the lengths of the other two sides of the triangle (often called "legs").  It does not matter which leg is chosen to be side "a" or side "b" due to the commutative property of addition, but "c" <u>must</u> be the hypotenuse.

a^2+b^2=c^2

Substituting known values, and simplifying...

a^2+(7)^2=(25)^2

a^2+49=625

Subtracting 49 from both sides to begin to isolate "a", and simplifying...

(a^2+49)-49=(625)-49

a^2=576

Applying the square root property to isolate "a", and simplifying/calculating...

\sqrt{a^2}=\pm \sqrt{576}

a=\pm 24

a=24  or  a=-24


Under the assumption that the triangle is an acute triangle, the adjacent side length is a positive value, so we reject the negative solution, deducing that the adjacent side length must be 24.

<em />

<em>Side note:  If there is more information in the context of the question that suggests that theta may be larger than 90°, then other factors will need to be taken into account.</em>

<h3><u>Step 4. Identifying the other trig ratios</u></h3>

Returning to the trig ratio definitions, we can identify the requested cosine and tangent ratios

\cos(\theta)=\dfrac{\bold{adjacent} \text{ side length}} {\bold{hypotenuse} \text{ length}} = \dfrac{24}{25}

\tan(\theta)=\dfrac{\bold{opposite} \text{ side length}} {\bold{adjacent} \text{ side length}}=\dfrac{7}{24}

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