Need help ASAP 3 question. WILL GIVE BRAINLIEST

PLZ HURRY TIMED QUIZ (20 POINT) NO LINKS!! Shelly is rolling a six-sided number cube and recording her results in a chart.

Tema [17]

The answer is B!!!!!!!

5 0

3 years ago

Give an example of two permutations of the same n labels 0; 1; : : : ; n ???? 1 that cannot be inorder and postorder traversal l

sertanlavr [38]

0.1 g g g. Gg g g g. Gg

8 0

3 years ago

A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent

kotykmax [81]

Answer:

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

Step-by-step explanation:

$\bar X_{1}=15$ represent the mean for sample 1

$\bar X_{2}=18$ represent the mean for sample 2

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=49$ sample size for the group 2

$n_{2}=64$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=49+64-2=111$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897$

P value

Since is a bilateral test the p value would be:

$p_v =2*P(t_{111}$

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

7 0

3 years ago

John scored 17 out of 30 in the Entrepreneurship test calculate his marks in percentage give your answer to one decimal place

Vesnalui [34]

Answer:

well, one john isnt that smart . he scored a 57% (0.5666....repeating)

Step-by-step explanation:

17 divided by

30

4 0

3 years ago

(-2) with an exponent of four equals what

charle [14.2K]

The answer is 16 because (-2*-2*-2*-2= 16)

6 0

3 years ago