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valentinak56 [21]
3 years ago
13

According to the given information, segment AB is parallel to segment DC and segment BC is parallel to segment AD.. Using a stra

ightedge, extend segment AB and place point P above point B. By the same reasoning, extend segment AD and place point T to the left of point A. Angles BCD and PBC are congruent by the Alternate Interior Angles Theorem. Angles PBC and BAD are congruent by the Corresponding Angles Theorem. By the __________ Property of Equality, angles BCD and BAD are congruent. Angles ABC and BAT are congruent by the Alternate Interior Theorem. Angles BAT and CDA are congruent by the Corresponding Angles Theorem. By the __________ Property of Equality, ∠ABC is congruent to ∠CDA. Consequently, opposite angles of parallelogram ABCD are congruent.
What properties accurately complete the proof?

Addition
Transitive

Reflexive
Reflexive

Substitution
Reflexive

Transitive
Transitive
Mathematics
1 answer:
ELEN [110]3 years ago
5 0
Something goes wrong with the question:
" segment AB is parallel to segment DC <span>and segment BC is parallel to segment AD" that is impossible when figure is built.</span>
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Answer:

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Which equation has the same solutions as the equation given below?
Lapatulllka [165]

Answer:

B

Step-by-step explanation:

Also solved eveything

(x+9)^2=49

x^2+18x+81=49

x^2+18x+32=0

a=1, b=18 and c=32

x= (-18 +/- Sqrt (18^2-4×32))/2

x= (-18 +/- Sqrt (324-128))/2

x= (-18 +/- Sqrt (196))/2

x= (-18 +/- 14)/2

x= (-18 +14)/2 = -4/2 =-2

OR

x= (-18 -14)/2 = -32/2 =-16

3 0
3 years ago
Read 2 more answers
Hello! Need help again
Shtirlitz [24]
Y=-x
Your welcome:):):)
4 0
3 years ago
Please include how to solve this!! Thanks you!
arlik [135]

Circle=27, triangle=18, and square=26

Start with the second question. If you divide 36 by 2, you get 18 which is the value for the triangle. Now since you know the value of the triange you subtract it from 45. (45-18=27) 27 is the value of the circle. Lastly, subtract 27 from 53 to get the value of the square (53-27=26). Hope this helps!

5 0
3 years ago
Directions: State whether or not (3, -2) is a solution to the following systems.
andrew11 [14]

(3, -2) is a solution to the system of equations x - 2y = 7 and 2x + 3y = 0, (3, -2) is not a solution to the system of equations  -x - y = -5 and 3x - 4y = 17 and (3, -2) is not a solution to the system of equations x + y = 1 and x - y = 6

<h3>How to determine the whether or not (3, -2) is a solution to the following systems?</h3>

The systems of equations are given as:

1. x - 2y = 7 and 2x + 3y = 0

2. -x - y = -5 and 3x - 4y = 17

3. x + y = 1 and x - y = 6

Next, we substitute (3, -2) for (x, y) in the system of equations.

So, we have:

<u>1. x - 2y = 7 and 2x + 3y = 0</u>

3 - 2 * -2 = 7 and 2 * 3 + 3 * -2 = 0

Evaluate

7 = 7 and 0 = 0

The above equation is true

Hence, (3, -2) is a solution to the system of equations x - 2y = 7 and 2x + 3y = 0

<u>2.- x - y = -5 and 3x - 4y = 17</u>

-3 + 2 = -5 and 3 * 3 + 4 * 2 = 17

Evaluate

- 1 = - 5 and 1 7 = 1 7

The above equation is false

Hence, (3, -2) is not a solution to the system of equations  -x - y = -5 and 3x - 4y = 17

<u>3. x + y = 1 and x - y = 6</u>

3 - 2 = 1 and 3 + 2 = 6

Evaluate

1 = 1 and 5 = 6

The above equation is false

Hence, (3, -2) is not a solution to the system of equations x + y = 1 and x - y = 6

Read more about system of equations at:

brainly.com/question/13729904

#SPJ1

8 0
1 year ago
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