If ABCD is a parallelogram, we have to prove that slope of
AB = CD and slope of BC = DA. Using the formula m = (y1-y2) / (x1-x2), the
slope of line segment AB = 0/-4, CD =
0/-4, BC = 1, DA = 1. Going back to the
condition, the slope we get for each line segment proves that ABCD is a
parallelogram.
Answer: 5m+10n+3
Step-by-step explanation:
Area of a circle is pi x r^2
R is the radius which is have the diameter: r = 10/2 = 5
Area of the full circle would be 3.14 x 5^2 = 3.14 x 25 = 78.5 square units.
A semi circle is half a full circle
Area of the semi circle = 78.5/2 = 39.25 square units.
Note that c is the hypotenuse of the blue triangle, and that the Pyth. Thm. states that (length of one leg)^2 + (length of the other leg)^2 = (hyp)^2.
Therefore, (hyp)^2 = c^2 = [2sqrt(x^2+3x)]^2 + 3^2, or
= 4(x^2+3x) + 9, or
= 4x^2 + 12x + 9 = (2x+3)^2
Taking the sqrt of both sides, c = plus or minus (2x+3). Eliminate -(2x+3) because the middle term of the square of this would be negative, in conflict with the given +12x.
c=2x+3 is the correct answer.
