Answer:
-2755
Step-by-step explanation:
If you look on the water bottle paper (It depends) you will find that it holds one of the amounts from 16.9<span> to 20 oz.
Hoped I helped!</span>
Answer:
Basically, when a scientific calculator displays a number as aEb, it means to move the decimal point in a as follows:
If b is positive, move the decimal point b units to the right.
If b is negative, move the decimal point b units to the left.
Step-by-step explanation:
Answer:
x = 23°
Step-by-step explanation:
Note: Complementary angles measure 90°
3x + (x - 2)° = 90°
=> 3x + x - 2° = 90°
=> 4x - 2° = 90°
Add the additive inverse of -2 to both sides of the equation
i.e 4x - 2° + 2° = 90° + 2°
=> 4x = 92°
Divide both sides of the equation by the coefficient of x which is 4
=> 4x/4 = 92°/4
x = 23°
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
