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kykrilka [37]
3 years ago
13

Your test scores in one class are 79?and 83.What possible scores can you earn on your next test to have a test average between 8

1 and 87 inclusive?
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
6 0

Answer:

83 and 84

Step-by-step explanation:

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What is the mean of 5,9,6,6,11,8,4
____ [38]

Answer:

7

Step-by-step explanation:

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4 years ago
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Which does NOT have a value of 4 when
12345 [234]

Answer:

3 beause when you dividend it -5.6+4(3) .

7 0
3 years ago
Carl deposited $5,142 into a savings account 20 years ago. The account has an interest rate of 3.8% and the balance is currently
Aleksandr [31]
Here is the formula you'll need
Total = Principal * (1 + (rate/n))^n*years
I don't know how to solve that for "n" so we'll use trial and error.

If compounded annually, total = <span> <span> <span> 10,841.24 </span> </span> </span>
If compounded quarterly, total = <span> <span> <span> 10,955.64 </span>
</span></span><span>If compounded monthly, total = </span> <span> <span> <span> 10,981.82 </span> </span> </span>
If compounded daily, total = <span> <span> <span> 10,994.58 </span> </span> </span>
Therefore the answer is "A", daily.

Source:
http://www.1728.org/compint3.htm


<span> </span><span><span> </span> </span>

3 0
3 years ago
3(x+4)=3(x)+3(4) distributive property
jok3333 [9.3K]

Answer:

3(x + 4) = 3(x) + 3(4)
3(x + 4) = 3x + 12
3x + 12 = 3x + 12

Subtract 12 from both sides
3x + 12 - 12 = 3x + 12 - 12

3x = 3x
3x - 3x = 3x - 3x
= 0

8 0
2 years ago
The sum of three numbers in <br> g.p. is 21 and the sum of their squares is 189. find the numbers.
sashaice [31]
Let the three gp be a, ar and ar^2
a + ar + ar^2 = 21 => a(1 + r + r^2) = 21 . . . (1)
a^2 + a^2r^2 + a^2r^4 = 189 => a^2(1 + r^2 + r^4) = 189 . . . (2)
squaring (1) gives
a^2(1 + r + r^2)^2 = 441 . . . (3)
(3) ÷ (2) => (1 + r + r^2)^2 / (1 + r^2 + r^4) = 441/189 = 7/3
3(1 + r + r^2)^2 = 7(1 + r^2 + r^4)
3(r^4 + 2r^3 + 3r^2 + 2r + 1) = 7(1 + r^2 + r^4)
3r^4 + 6r^3 + 9r^2 + 6r + 3 = 7 + 7r^2 + 7r^4
4r^4 - 6r^3 - 2r^2 - 6r + 4 = 0
r = 1/2 or r = 2
From (1), a = 21/(1 + r + r^2)
When r = 2:
a = 21/(1 + 2 + 4) = 21/7 = 3
Therefore, the numbers are 3, 6 and 12.
3 0
3 years ago
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