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valentina_108 [34]
3 years ago
5

During one snowy month a kentucky school held classes 9/11 of possible the school days if there are 22 possible school days how

many days was school held in this month
Mathematics
1 answer:
SOVA2 [1]3 years ago
5 0
This question isn't phrased correctly, but I will assume it's asking about common denominators with fractions.

9/11 1/22

18/22 1/22

18 school days.
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podryga [215]

Answer:

45 degrees

Step-by-step explanation:

AOB = 140°

and an the angle bisector(OC) is a line which will divide AOB into 2 equal angles

which is 140÷2= 70

and if AOD = 25 then COD= 70-25

= 45 degrees

hope it helps

3 0
2 years ago
Consider three events A, B and C with following properties.
lisov135 [29]
By the inclusion/exclusion principle,

\mathbb P(D)=\mathbb P(A\cup B\cup C)
\mathbb P(D)=\mathbb P(A)+\mathbb P(B)+\mathbb P(C)-\bigg(\mathbb P(A\cap B)+\mathbb P(A\cap C)+\mathbb P(B\cap C)\bigg)+\mathbb P(A\cap B\cap C)
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\mathbb P(D)=\dfrac{16}{39}\neq1

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5 0
3 years ago
Serena’s average speed during her training run was 8 kilometers per hour over the 2 hours that she ran. What was the total dista
Volgvan

Step-by-step explanation:

so, we just enter the given data into the given formula. and then calculate. it does not get easier than that.

d = 8km/h × 2h = 16km

Serena ran 16km in these 2 hours.

7 0
2 years ago
If MN = x+4 and DE = 3x-2, find x. (More info in pic)
algol [13]

Answer:  D) 10

============================================================

Explanation:

I'm assuming points M and N are midpoints of segments FD and FE respectively. If that's the case, then segment DE is twice as long compared to segment MN. We consider MN to be a midsegment.

So,

DE = 2*(MN)

3x-2 = 2*(x+4)

3x-2 = 2x+8

3x-2x = 8+2

x = 10

6 0
2 years ago
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RideAnS [48]

Answer:

the mean is 26

Step-by-step explanation:

8 0
2 years ago
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