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MatroZZZ [7]
3 years ago
8

Plz plz help meeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics
1 answer:
Marizza181 [45]3 years ago
5 0
Y = -1/3x -1. The formula is y = mx + b where m is the slope and b is the y intercept.
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5/8 brainliest im giving if u get it right :D
blondinia [14]

Well basically if they lost 8 points and gained 6, they have -2 points.

3 0
3 years ago
Read 2 more answers
Which equation is y=(x+3)2+(x+4)2 rewritten in vertex form
Julli [10]
Vertex coordinates: (h, k)

Vertex form: y = a(x-h)^2 + k

y = 2(x+3) + 2(x+4)

Use distributive property:

y = 2((x+3)+(x+4))

Simplify:

y = 2(2x+7)

y = 4x+14

This is slope - intercept form, not vertex form. Vertex form is for quadratic equations - this is a linear equation.

Answer (in slope - intercept form):

y = 4x+14
3 0
3 years ago
QUESTION 8 Write an inequality to represent the real-world problem. Then explain how you created the inequality. You have caviti
Marizza181 [45]

Answer:

I can give you alittle head start. I hope it kinda helps.

Step-by-step explanation:

Dentist A: 50 + 20x

Dentist B: 70 + 5x

It cost 20 more dollars for the visit and 15 dollars less for each cavaty at Dentist B.

6 0
3 years ago
A team of ten cyclists wants to choose leaders. in how many ways can the team choose one captain and then two assistants?
AURORKA [14]

Answer:

The team can look at who has been there the longest to pick the captian, and then the assistants can be two people who the captian would best work with. Also look for loyalty and integridy, honestly and good traits that have been shown.

4 0
3 years ago
The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​
Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is \dfrac{15}{2}.

To find:

The sum of first six terms.​

Solution:

We have,

S_2=6

S_4=\dfrac{15}{2}

Sum of first n terms of a GP is

S_n=\dfrac{a(1-r^n)}{1-r}              ...(i)

Putting n=2, we get

S_2=\dfrac{a(1-r^2)}{1-r}

6=\dfrac{a(1-r)(1+r)}{1-r}

6=a(1+r)                    ...(ii)

Putting n=4, we get

S_4=\dfrac{a(1-r^4)}{1-r}

\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}

\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}

\dfrac{15}{2}=6(1+r^2)            (Using (ii))

Divide both sides by 6.

\dfrac{15}{12}=(1+r^2)

\dfrac{5}{4}-1=r^2

\dfrac{5-4}{4}=r^2

\dfrac{1}{4}=r^2

Taking square root on both sides, we get

\pm \sqrt{\dfrac{1}{4}}=r

\pm \dfrac{1}{2}=r

\pm 0.5=r

Case 1: If r is positive, then using (ii) we get

6=a(1+0.5)  

6=a(1.5)  

\dfrac{6}{1.5}=a  

4=a

The sum of first 6 terms is

S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}

S_6=\dfrac{4(1-0.015625)}{0.5}

S_6=8(0.984375)

S_6=7.875

Case 2: If r is negative, then using (ii) we get

6=a(1-0.5)  

6=a(0.5)  

\dfrac{6}{0.5}=a  

12=a  

The sum of first 6 terms is

S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}

S_6=\dfrac{12(1-0.015625)}{1.5}

S_6=8(0.984375)

S_6=7.875

Therefore, the sum of the first six terms is 7.875.

5 0
3 years ago
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