Answer:
Linearly, because the table shows that the sunflowers increased by the same amount each month
Step-by-step explanation:
Given the table

Note that months change one-by-one (21-1, 3-2=1, 4-3=1).
Also
![17.2-15=2.2\ [\text{from month 1 to month 2}]\\ \\19.4-17.2=2.2\ [\text{from month 2 to month 3}]\\ \\21.6-19.4=2.2\ [\text{from month 3 to month 4}]](https://tex.z-dn.net/?f=17.2-15%3D2.2%5C%20%5B%5Ctext%7Bfrom%20month%201%20to%20month%202%7D%5D%5C%5C%20%5C%5C19.4-17.2%3D2.2%5C%20%5B%5Ctext%7Bfrom%20month%202%20to%20month%203%7D%5D%5C%5C%20%5C%5C21.6-19.4%3D2.2%5C%20%5B%5Ctext%7Bfrom%20month%203%20to%20month%204%7D%5D)
This means the number of sunflowers increases linearly, because the table shows that the sunflowers increased by the same amount each month
Answer:
y=1/4x+3
Step-by-step explanation:
To find the inverse, switch x and y or f(x)
f(x)=4x-12
y=4x-12
x=4y-12
Add 12 to both sides
x+12=4y-12+12
x+12=4y
Divide both sides by 4
x+12/4=y
1/4x+12/4=y
1/4x+3=y
y=1/4x+3
Answer: p = 6
Step-by-step explanation:
HI !
px + 3y - ( p-3)=0
a₁ = p , b₁ = 3 , c₁ = - (p-3)
=====================
12x + py - p=0
a₂ = 12 , b₂ = p , c₂ = -p
since , the equations have infinite solutions ,
a₁/a₂ = b₁/b₂ = c₁/c₂
p/12 = 3/p = p-3/p
--------------------------------------
p/12 = 3/p
cross multiply ,
p² = 36
p = √36
p = 6
for the value of p = 6 , the equations will have infinitely many solutions
Answer:
70,110,110,110
Step-by-step explanation:
I'm Asian and I was less than 5 minutes
Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Step-by-step explanation:
Total number of students = 8
Number of student who has passed Exam P/1 = 1
Number of student who has passed Exam FM/2 = 1
No student has passed more than one exam.
According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.
So, Probability will be

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.