Question

Kamal made a replica of the Kaaba located in Mecca, Saudi Arabia. The dimensions of his replica are 24 long by 21

Answer 1

Answer:

Surface area of the actual Kaaba in meters is 9,270,000 m^2.

Step-by-step explanation:

Here, the dimension of the Kaaba are:

Length = 24 , Width = 21,  Height = 30

Now, here the scale is 1  = 50 meters

So, the actual length of the Kaaba  = 24 x ( 50 m) = 1200 m

the actual width of the Kaaba  = 21 x ( 50 m) = 1050 m

the actual height of the Kaaba  = 30 x ( 50 m)  = 1500 m

The surface area of the actual Kaaba   = 2 lw + 2 lh +2 hw  

= 2 ( 1200 x 1050) + 2 ( 1050 x 1500) + 2 (1500 x 1200)

=  2,520,000 + 3,150,000 + 3,600,000

= 9,270,000 sq m

Hence,  surface area of the actual Kaaba in meters is 9,270,000 m^2.

Answer 2

Answer:  9270000 m²

Step-by-step explanation:

Given : The dimensions of Kamal's replica are 24 long by 21  wide by 30  high.

If the scale factor is 50, then the dimension of the actual Kaaba in meters will be :

Length = 24 x 50 = 1200 m

Width = 21 x 50 = 1050 m

Height = 30 x 50 = 1500 m

Surface area of rectangular prism : 2 (lw +wh+lh) , where l= length , w = width and h = height.

⇒ Surface area of the actual Kaaba = 2[(1200)(1050)+(1050)(1500)+(1200)(1500)] m²

= 2(4635000) m²

= 9270000 m²

Hence, the surface area of the actual Kaaba = 9270000 m²