Answer:
<h3>A. y=-2x+3z+25</h3>
Step-by-step explanation:
Isolate the term of x and y from one side of the equation.
<u>To solve:</u>

<h3>2x+y-3z=25</h3>
<u>First, you have to subtract by 2x-3z from both sides.</u>

<u>Solve.</u>

- <u>Therefore, the correct answer is "A. y=-2x+3z+25".</u>
I hope this helps, let me know if you have any questions.
Answer:
x=12 and the measure is 144
Step-by-step explanation:
Can i get an owa owa?
9514 1404 393
Answer:
K(-14 1/3, -34 2/3)
Step-by-step explanation:
The division ratio says ...
(L -J)/(K -L) = 3/2
2(L -J) = 3(K -L)
5L -2J = 3K
K = (5L -2J)/3
K = (5(-15, -20) -2(-16, 2))/3 = (-75+32, -100-4)/3 = (-43/3, -104/3)
K = (-14 1/3, -34 2/3)
9514 1404 393
Answer:
- graph is shown below
- absolute max and min do not exist
- local max: 0 at x=0
- local min: -500/27 ≈ -18.519 at x=10/3
Step-by-step explanation:
The function is odd degree so has no absolute maximum or minimum. It factors as ...
g(x) = x^2(x -5)
so has zeros at x=0 (multiplicity 2, meaning this is a local maximum*) and x=5.
Differentiating, we find the derivative of g(x) is zero at x = 0 and x = 10/3.
g'(x) = 3x^2 -10x = x(3x -10) ⇒ x=0 and x=10/3 are critical points
The value of g(10/3) is a local minimum. That value is ...
g(10/3) = (10/3)^2((10-15)/3) = -500/27 ≈ -18.519
__
The local maximum is (0, 0); the local minimum is (10/3, -500/27). The graph is shown below.
_____
* When a root has even multiplicity, the graph does not cross the x-axis. That means the root corresponds to a local extremum. Since this is the left-most root of an odd-degree function with a positive leading coefficient, it is a local <em>maximum</em>. (The function is <em>increasing</em> left of the left-most turning point.)
Answer:
18
Step-by-step explanation:
=2(cot²A+1)
=2cosec²A. [` . ` cot²A+1=cosec²A] =2(1/sinA)²
[' . 'cosecA=1/sinA]
=2×3²/1
=2cot²a+2=2×8+2=16+2=18