Question

Enter an equation in standard form for the line. Slope is -4, and (-9, -12) is on the line.

Answer 1

Answer:

$4x + y +48=0$

Step-by-step explanation:

We are here given the slope of the line and one point through which it passes . The slope of the line is -4 and the point is (-9,-12) .

Here we can use the point slope form of the line as ,

$\sf\longrightarrow y-y_1 = m(x-x_1)$

Substitute the respective values ,

$\sf\longrightarrow y - (-12) = -4\{ x -(-9)\}$

Simplify LHS and RHS ,

$\sf\longrightarrow y + 12 = -4( x +9)$

Open the brackets in RHS ,

$\sf\longrightarrow y + 12 = -4x -36$

Add 36 and 4x to both sides ,

$\sf\longrightarrow \underline{\boxed{\orange{\sf 4x + y + 48 =0}}}$