Line $m$ is parallel to line $n$ and the measure of $\angle 1$ is $\frac 18$ the measure of $\angle 2$. What is the degree measu
2 answers:
The degree measure of the angle labelled 5; m<5 = 116°.
<h3>What is the measure of the angle labelled 5 in the task content?</h3>The angle measure of the angle labelled 5 as in the complete task content in the attached image can be determined as follows;
It follows from the complete task content that; that the measure of angle 2 is; 64°.
On this note, it follows from the sum of angle measures on a straight line theorem that; m<4 = 180° - 64° = 116°.
Additionally, it follows from the congruence of alternate angles theorem that <4 and <5 are congruent and hence, their measures are equal.
Therefore, m<5 = 116°.
Read more on congruence of angles;
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The angle of m∠5 is 116 degrees.
<h3>How to find angles when parallel lines are cut by a transversal?</h3>When parallel lines are cut by a transversal, angle relationships are formed. This include corresponding angles, alternate angles , vertical angles etc.
Therefore, line m and n are parallel lines cut by the a transversal.
Hence,
m∠2 = 64 degrees
Therefore,
m∠5 = m∠4 (alternate angles)
Therefore,
m∠5 + m∠2 = 180
m∠5 = 180 - 64
m∠5 = 116 degrees.
learn more on parallel lines here: brainly.com/question/26402932
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Answer:
As this question is incomplete, but we will try to solve this question by adding our own data to understand the concept of the problem.
Explanation is given below
Step-by-step explanation:
As this question is incomplete, but we will try to solve this question by adding our own data to understand the concept of the problem.
In order to answer this question we need to have the dimensions of the box.
Let's suppose there are 6 outside surfaces of the box and are equal in dimension including the bottom side which Jan wants to varnish.
So,
Let's suppose,
Surface area of the cube = 6
Here, Surface area = 275 square inch
Surface area of the cube = 6 = 275 square inch
= 275/6 = 45.833
a =
a = 6.77 inches
Now, for the amount of the varnish, we need the spreading rate of the varnish to be used on the box,
Let's suppose it is = 11 square incher per litre.
So,
Required Varnish = Surface area / Spreading rate
Required varnish = 275 / 11
Required varnish = 25 liters
If the 1 container of varnish contains 25 liters then it will be sufficient to protest the outside surfaces of the box.