If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:

Referring to a standard normal distribution table, and using z = 0.66, we find:

Therefore

The answer is: 0.2546
Depends on what type if sunflower seeds they are some don't have calories
Answer:
14/15
Step-by-step explanation:
simple
3/5 + 1/3= 14/15
1 and 8 are because they are alternate exterior angles
Answer:
A is the correct answer.
Step-by-step explanation:
y and x meet on those numbers. And i did the test.
hope this helps