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DENIUS [597]
3 years ago
6

Statistics

Mathematics
1 answer:
Lisa [10]3 years ago
6 0
Add them then take away 20
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Find the difference. Simplify. Combine Like Terms.
Ivan

Answer:

\huge{ \fbox{ \sf{ - 2y - 30}}}

Step-by-step explanation:

\star{ \sf{ \: (4y - 10) - (6y + 20)}}

\text{Step \: 1 }\:  :  \sf{While \: subtracting \: sign \: of \: each \: term \: of \: the \: second \: expression \: changes}

\hookrightarrow{ \sf{4y - 10 - 6y - 20}}

\text{Step \: 2 \:  :  \sf Collect \: like \: terms}

\sf{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}

\hookrightarrow{ \sf{4y - 6y - 10 - 20}}

\hookrightarrow{ \sf{ - 2y - 10 - 20}}

\text{Step \: 3 \:  :  \sf{Calculate}}

\underline{ \text{Remember!}}  :  \sf{The \: negative \: integers \: are \:always \: added \: but \: posses \: the \: negative \: ( - ) \: sign.}

\hookrightarrow{ \sf{ - 2y - 30}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

5 0
4 years ago
The amount of space in the dog carrier shown can be found by multiplying it's width length and height write the amount of space
Leokris [45]
Given:
Length = 2 ft
Width = 2 ft
Height = 2 ft

Volume = Length * Width * Height
V = 2 ft * 2 ft * 2 ft 
V = 8 ft³ or 8 cubic feet

In exponential form:
V = (2ft)³
V = 8 ft³
4 0
3 years ago
Suppose x has a distribution with μ = 40 and σ = 12. (a) If random samples of size n = 16 are selected, can we say anything abou
Temka [501]

Answer:

a: no the sample size is too small

b:  Yes, the distribution is normal with a mean of 40 and standard deviation of 12

Step-by-step explanation:

a:  If n < 30, we need to know that the sample is normally distributed or else we can't determine anything.  When sample sized get very large, they usually resemble normally distributed data sets so we can still make conjectures even if the data isn't officially normally distributed

b: The question tells us that the sample is normally distributed, so even though n < 30, we can still make conjectures about the population

7 0
3 years ago
Help with all please
seropon [69]

a) First, draw a graph. The x axis should be numbered: 0, 1, 2, 3, 4, 5, 6, 7, 8. Each number is the last digit of the year. For each year, there is one average score that has to be plotted. Number the y axis of the graph from 0-600, by increments of 50, or something around there. Now, with each year (each x value) place the dot as high as the average score. Repeat with all years. DO NOT draw a line to connect them. A scatter plot is a bunch of points that are not connected.

b) Use the form (y2-y1)/(x2-x1) where (x1,y1) (x2,y2) are any two points from 2001-2006. It does not matter which points, pick any, and assign each of the numbers x1,y1 and x2,y2. Plug it in to the equation, and simplify. This is your slope, also called m. Now plug m into the equation y-y1=m(x-x1) where y1 and x1 are the x and y coordinates of any point from 2001 to 2006. x and y dont have values themselves, they stay there. Now distribute the m into the parenthesis, add y1 to both sides (to cancel it out on the left), and you should be left with the same equation, but now in y=mx+b form. B is where the line crosses the y axis, so put a point on the vertical axis where b is. M is your slope, so every time you go to the right one number, go up M numbers. Draw another point. Repeat this until you can connect these new dots into a line. This line should be on the same graph as your other points, but might not touch all of the scatter plot points. That's still okay, just leave it as is.

c) Find the point where x=6 (meaning the year is 2006) on your line. Find the average test score for that year by seeing where the point lines up along the y axis (draw a straight line from the point to the left to see, if you have to). Take that number and add 1m (the m is the number you used in step B) to it. This predicts what the average score might be after 1 (that's why the 1 is there) year. This is a predicted value, and might not be perfectly correct!! Write/record how close this new, predicted, score is to the actual number, 515, which can be found on the scatter plot.

d) repeat step C exactly as before (still use the year 2006) , but add 4m instead of 1m, to get the predicted score 4 years after 2006 (2010), instead of 1 year after (2007).

I hope I have been of some help! Best of luck!!! :)

3 0
3 years ago
Please help i beg i never get these right
Anuta_ua [19.1K]

Answer:

\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}

Step-by-step explanation:

Given

\sin(105^o)

Required

Solve

Using sine rule, we have:

\sin(A + B) = \sin(A)\cos(B) + \sin(B)\cos(A)

This gives:

\sin(105^o) = \sin(60 + 45)

So, we have:

\sin(60 + 45) = \sin(60)\cos(45) + \sin(45)\cos(60)

In radical forms, we have:

\sin(60 + 45) = \frac{\sqrt 3}{2} * \frac{\sqrt 2}{2} + \frac{\sqrt 2}{2} * \frac{1}{2}

\sin(60 + 45) = \frac{\sqrt 6}{4} + \frac{\sqrt 2}{4}

Take LCM

\sin(60 + 45) = \frac{\sqrt 6 + \sqrt 2}{4}

Rewrite as:

\sin(60 + 45) = \frac{\sqrt 2 + \sqrt 6}{4}

Hence:

\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}

3 0
3 years ago
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