Rewrite each expression using each base only once.
(-6)^12 * (-6)^3 * (-6)^2
(-6)^(12+3+2)
(-6)^(17)
Answer:
(-6)^(17)
2^2 * 2^7 * 2^0
(2)^(2+7+0)
(2)^(9)
Answer:
(2)^(9)
Simplify each expresion.
5c^4 * c^6
5*c^(4+6)
5*c^(10)
Answer:
5*c^10
(-2.4n^4)(2n^-1)
(-2.4*2)(n^4)(n^-1)
(-2.4*2)(n^(4+(-1))
(-4.8)(n^(4-1))
(-4.8)(n^(3))
Answer:
(-4.8)(n^(3))
(4c^4)(ac^3)(-3a^5c)
((4)*(-3))*(c^(4+3+1))*(a^(1+5))
(-12)*(c^(8))*(a^(6))
Answer:
(-12)*(c^8)*(a^6)
a^6b^3 * a^2b^-2
(a^(6+2))*(b^(3+(-2)))
(a^(8))*(b^(3-2))
(a^(8))*(b^(1))
(a^8)*(b)
Answer:
(a^8)*(b)
Answer:
The binomial: (x-2) (second option of the list) is a factor of the given trinomial
Step-by-step explanation:
You are looking for two binomial factors of the form; (x+a) and (x+b), with values "a" and "b" such that:
Their product "a times b" results in: "+14" (the numerical term in the initial trinomial ,
and their combining "a+b" results in "-9" (the coefficient in the middle term of the trinomial)
Such number "a" and "b" are: "-2" and "-7".
We can see by multiplying the binomials formed with these numbers:
(x-2) and (x-7) that their product indeed renders the original trinomial:
therefore, the binomials (x-2) and (x-7) are factors of the given trinomial.
The only one shown among the four possible options is then: (x-2)
Answer:
330
or -30
Step-by-step explanation:
Answer:
a
Step-by-step explanation:
because I have did this at school