This is an approximately bell-shaped distribution. The highest bar is in the center, with height = 12. Just to its left and right are bars of heights 6 and 5. At the extremes are bars of heights 2 and 1.
If the highest bar was on the left, it would be skewed left (and if it was on the right, skewed right). A uniform distribution would more or less have the same height level over all the bars.
Distributive property is
a(b+c)=ab+ac so
first, distribute
remember than (-) times (-)=(+)
-5(3x-8)=(-5)(3x)+(-5)(-8)=-15x+(+40)=-15x+40
so it is -15x+40=-45
the answe ris B
Answer:
Length of rectangle = 16 cm
Width of rectangle = 4 cm
Step-by-step explanation:
Given:
Area of rectangle = 64 cm²
Find:
Length and width
Computation:
Assume;
Length of rectangle = a
So,
Width of rectangle = a -12
Area of rectangle = l x b
So,
a(a-12) = 64
a² - 12a - 64 = 0
a² - (16-4)a - 64 = 0
a² - 16a+ 4a - 64 = 0
a (a-16) + 4(a-16)= 0
(a-16)(a+4) = 0
a= 16 , a = -4
So,
Length of rectangle = 16 cm
Width of rectangle = a -12
Width of rectangle = 16 -12
Width of rectangle = 4 cm
Answer: 975
Step-by-step explanation:
The cost would be 975
