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djverab [1.8K]
3 years ago
8

During a backgammon game, Jimmy rolled two dice on the board. Find the probability that the sum obtained was greater than 8 give

n that the number on one die was a 6
Mathematics
1 answer:
True [87]3 years ago
5 0

Answer:

<h2>2/3</h2>

Step-by-step explanation:

This problem bothers on probability

Given that two dice are expected to give an outcome of sum greater than 8

But in the problem statement the first die is already settled since it is showing 6 already.

Now for the second die, the possible outcomes that will add up with the first die to produce a figure greater than 8 are (3,4,5,6)  

The probability of obtaining either of these numbers is 4/6= 2/3

<em>Having the first die settled, this means that the probability of obtaining a sum of 8 is 2/3</em>

<em />

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3 years ago
Solve for x. 3(x + 2) + 4(x - 5) = 10 x = 36/7 x = 24/7 x = 16/7 x = 9/7
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3 years ago
I NEED HELP QUICKLY!!! What is the sum of the first 140 positive multiples of 3?
garri49 [273]

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C

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