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Likurg_2 [28]
3 years ago
11

A nonvolatile solute is dissolved in benzene so that it has a mole fraction of 0.139. What is the vapor pressure of the solution

? (P° of benzene is 26.5 torr)
Chemistry
1 answer:
lapo4ka [179]3 years ago
7 0

Answer:

The vapor pressure of the solution is 3.69 torr

Explanation:

Step 1: Data given

Mole fraction of benzene in the solution = 0.139

P° of benzene is 26.5 torr

Step 2: Calculate the vapor pressure of the solution

Psolution = Xbenzene * P°benzene

⇒with Psolution = the vapor pressure of the solution

⇒with Xbenzene = the mole fraction of benzene = 0.139

⇒with P°benzene = the vapor pressure of pure benzene = 26.5 torr

Psolution = 0.139 * 26.5 torr

Psolution = 3.69 torr

The vapor pressure of the solution is 3.69 torr

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inessss [21]

Answer:

ver explicacion

Explanation:

El elemento que tiene el número atómico 56 en la tabla periódica del bario. El bario es un elemento del grupo dos.

Se combina con el cloro para formar cloruro de bario. que tiene la fórmula BaCl2 de acuerdo con la valencia de ambos elementos.

El cloruro de bario es un compuesto iónico.

5 0
3 years ago
1) You are asked to make 10 miles of iron (Fe) from iron oxide (Fe2O3) and excess carbon monoxide (CO). Fe2O3(s) + 3CO(g)—> 2
Inessa05 [86]

For both of them, used the balanced equation and it’s mole ratio to convert whatever you need to into moles. See the attacked work.

1) D 5 mols

2) A 0.55 mols

8 0
3 years ago
Which of the following is the largest volume? (B?)
vekshin1
Yeah, it would be B (1.2 x 102 m^3) because the measurement gave it away even though other numbers were higher, however, the measurements for those were smaller in size.
6 0
3 years ago
How many moles in 6.57 x 10^24 formula units of NaCl?
laiz [17]

Answer:

3.955*10^48

Explanation:

1 mole of a substance gives 6.02*10^23/6.57*10^24 will give x then cross multiply the answer. is 3.955*10^48

8 0
3 years ago
Consider this reaction 2Mg(s)+O2(g) ———> 2MgO(s) What volume (in milliners) of gas is required to react with 4.03 g Mg at STP
nydimaria [60]

The volume of a gas that is required  yo react with 4.03 g mg  at STP  is 1856 ml



calculation/

  • calculate the moles of Mg used

     moles=mass/molar mass

moles of Mg is therefore=4.03 g/  24.3 g/mol=0.1658  moles

  • by use of mole ratio of Mg:O2  from  the equation  which is 2:1

  the moles 02=0.1679 x1/20.0829 moles

  • at STP  1 mole of a gas= 22.4  l

                            0.0895 moles=? L

  • by cross multiplication
  • =0.0895 moles  x22.4 l/  1 mole=1.8570 L

into Ml = 1.8570 x1000=1856  ml  approximately to 1860

6 0
3 years ago
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