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Sonja [21]
3 years ago
13

Can anyone draw a Lewis Structure for caprolactam (C6H11NO)

Chemistry
1 answer:
andreev551 [17]3 years ago
8 0
Answer: in pic
explanation:

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How many moles of copper (Cu) are in 65.8 g Cu?
Veseljchak [2.6K]
<h2><u>Answer:</u></h2>

The correct answer is A) 1.04 mol Cu

{65.8 g     /   63.55 g/mol}

= 1.04 mol Cu

Explanation:

In  63.55  g  of copper metal there are  1 m o l  of  C u  atoms. By dividing the mass of Cu and molar mass, we can easily get the number of moles.


5 0
3 years ago
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A type of plate boundary that is transform faults (easily seen where they cut at right angles to the mid-ocean ridges) A.) conve
34kurt
The answer is Option C (Divergent Plate Boundary)

Mapping efforts have shown that mid-ocean ridges<span> are discontinuous structures that cut at </span>right angles<span> to its length at various transform faults. They typically </span><span>demarcate the </span>boundary <span>between two tectonic plates, and are therefore called </span>divergent<span> plate </span>boundaries.
8 0
3 years ago
What contribution to atomic theory resulted from albert einstein’s work?
gizmo_the_mogwai [7]

Answer: A new model of the atom that described electrons as being in a cloud

Explanation:

7 0
3 years ago
Read 2 more answers
+ H₂O
trapecia [35]

Answer:

None of these are correct, because there is no way to balance this equation, but I hope these steps help you figure out your answer.

Explanation:

Count out the single amounts of elements you have on both sides of the equation. To be balanced, you need to have the exact same for each element.

Before balanced Left side.

Cl-2

O-8

H-2

Before balanced right side.

H-1

Cl-1

O-3

That means we need to increase Hydrogen, Chlorine and Oxygen on the right for sure and see how that affects the equation. You can keep adding the Coefficients until the # of elements begin to match on each side.  

(I tried to balance this equation, it doesn't work, there is too much on the reactants side for what the product is.)

8 0
2 years ago
How many molecules are there in 79g of Fe2O3?
weqwewe [10]
There are approximately 160 grams in 1 mol of fe203 molecules therefore there would be 79/160 = 0.49375 mols of fe203 molecules in 79 grams therefore 5 atoms in total for each molecule of fe203 therefore 79/160 *5 =79/32=2.46875 mols in atoms
6 0
3 years ago
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