I need this answer and FAST! This is the problem: 4=8-3h

1 answer:

3 0

Rememeber, you can do anything to an equation as long as you do it to both sides

4=8-3h
minus 8 both sides
-4=-3h
divide both sides by -3
-4/-3=h
4/3=h
h=4/3 or about 1.333333333333333333333333333

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Plz help i need help asap

tiny-mole [99]

Answer:

20 outcomes

Step-by-step explanation:

the outcomes of the first times the outcomes of the second

= 4×5

= 20

5 0

2 years ago

Can anyone help me figure out how to do this

3241004551 [841]

Answer:

$133m^2$

Step-by-step explanation:

What if i say NO?

3*3=9

8+3=11

12-3=9

9*11=99

2 area coverd so far

99+9=108

7*2=14

108+14=122

Lastly the tir

10-7=3

11-3-2=6

6*4=24

24/2=12

$133m^2$

8 0

2 years ago

Simplify completely: 8x+4/x^3+23÷4x^2-10x-6/9-x^2

Helen [10]

Answer:

The simplified form is: $-x^2-2x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{2}{3}$

Step-by-step explanation:

To simplify the expression given we, need to open the brackets, and if there is power term. Then we need to group all the like terms and then arrange in the descending order of powers of the given expression.

Now the expression that is given to us is:

$8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2$

Here we will simplify it by grouping the like terms, as follows:

$8x+\frac{4}{x^3}+\frac{23}{4x^2}-10x-\frac{6}{9}-x^2\\=-x^2+8x-10x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{6}{9}=-x^2-2x+\frac{4}{x^3}+\frac{23}{4x^2}-\frac{2}{3}$