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mina [271]
3 years ago
7

Find the distance between the points (–3, 2) and (0, 3).

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

Answer: \sqrt{10}\ units

Step-by-step explanation:

You need to use the following formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given the points  (-3, 2) and (0, 3), you can identify that:

x_2=-3\\x_1=0\\\\y_2=2\\y_1=3

Then, the final step is to substitutes these coordinates into the formula.

So, the distance between the given points is:

d=\sqrt{(-3-0)^2+(2-3)^2}\\\\d=\sqrt{10}\ units

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A, because negative is not rational
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djyliett [7]

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3 years ago
Let P = 0.50.30.50.7 be the transition matrix for a Markov chain with two states. Let x0 = 0.50.5 be the initial state vector fo
pav-90 [236]

Answer:

Probability distribution vector = \left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)

Step-By-Step Explanation

If P=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right)  is the transition matrix for a Markov chain with two states.  

x_{0}=\left(\begin{array}{c}0.5\\ 0.5 \end{array} \right)  be the initial state vector for the population.

X_{1}=P x_{0}=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right) \left(\begin{array}{c}0.5\\ 0.5 \end{array} \right) =\left(\begin{array}{c}0.4\\ 0.6 \end{array} \right)  

X_{2}=P^{2} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)  

X_{3}=P^{3} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)  

X_{30}=P^{30} x_{0}=\left(\begin{array}{c}0.37499\\ 0.625 \end{array} \right)  

In the long run, the probability distribution vector Xm approaches the probability distribution vector \left(\begin{array}{c}0.375\\ 0.625 \end{array} \right) .

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4 0
3 years ago
PLSSSS HELP<br><br> X+18=2x+17
kifflom [539]

Answer:

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8 0
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